Question

我有一个PurchaseOrder实体，它与ArticleOrder实体具有OneToMany关系。此外，ArticleOrder实体不仅包含订单和商品ID，还包含金额。此外，ArticleOrder实体与另一个名为ArticleSupplier的实体具有OneToMany关系。这样每个文章的订购金额可以拆分为多个供应商。现在我想构建一个表单来解决这个问题。所以我创建了三种表单类型：

仅包含ArticleOrders的嵌入式集合的那个：

 public function buildForm(FormBuilderInterface $builder, array $options)
{

    $builder->add('purchaseOrders', 'collection', array('type' => new ProducedAmountOrderArticleType()));
}

public function setDefaultOptions(OptionsResolverInterface $resolver)
{
    $resolver->setDefaults(array(
        'data_class' => 'Acme\AppBundle\Entity\PurchaseOrder',
    ));
}

包含ArticleSupplier条目的嵌入式集合的一个：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder->add('articleOrderReferences', 'collection', array('type' => new ProducedAmountOrderSubArticleType()));

}

public function setDefaultOptions(OptionsResolverInterface $resolver)
{
    $resolver->setDefaults(array(
        'data_class' => 'Acme\AppBundle\Entity\ArticleOrderReference',
    ));
}

还有一个用于ArticleSupplier Amount输入字段：

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder->add('produced');

}

public function setDefaultOptions(OptionsResolverInterface $resolver)
{
    $resolver->setDefaults(array(
        'data_class' => 'Acme\AppBundle\Entity\AOSupplierReference',
    ));
}

树枝代码：

<span class="purchaseOrders">
                    {% for purchaseOrder in form.purchaseOrders %}
                        <span class="articleOrderReferences">
                            {% for articleOrderReference in form.articleOrderReferences %}
                                {{ form_errors(articleOrderReference.produced) }}
                                {{ form_widget(articleOrderReference.produced, { 'attr': {'class': 'input-mini'} }) }}
                            {% endfor %}<br>
                        </span>

                    {% endfor %}
                </span>

控制器：

           $form = $this->createForm(new ProducedAmountOrderType(), $order);

//         // process the form on POST
//         if ($request->isMethod('POST')) {
//          $form->bind($request);
//          if ($form->isValid()) {

//              $em = $this->getDoctrine()->getManager();
//              $em->persist($order);
//              $em->flush();

//              return $this->redirect($this->generateUrl('order', array('id' => $orderId )));
//          }
//         }

        return $this->render('AcmeAppBundle:ProducedAmount:index.html.twig', array(
                'form' => $form->createView(),
                'order' => $order,
                'articles' => $articles,
        ));

我评论了发布的请求，因为这只会导致空白页面。现在我总是得到这个错误信息：

Method "articleOrderReferences" for object "Symfony\Component\Form\FormView" does not exist in AcmeAppBundle:ProducedAmount:index.html.twig at line 150

我做错了什么？

Answer 1

此：

{% for articleOrderReference in form.articleOrderReferences %}

应该是：

{% for articleOrderReference in **purchaseOrder**.articleOrderReferences %}

放弃*当然。我试着大胆一点。

多个嵌入式集合

1 个答案: