我对edititng嵌入式收藏表格有疑问。我有两个具有多对一关系的对象。当我创建一个对象" Good"与相关的"照片"都成功了。当我通过添加一些新照片来更新Good对象时,一切正常。但是,如果我在删除更新照片后尝试删除某个Good对象中的一张照片。
Good.php
/**
* @ORM\OneToMany(targetEntity="Photo", mappedBy="good", cascade={"persist", "remove"})
**/
private $photos;
/**
* Add photos
*
* @param \VDKP\Site\BackendBundle\Entity\Photo $photos
* @return Good
*/
public function addPhoto(\VDKP\Site\BackendBundle\Entity\Photo $photos)
{
$photos->setGood($this);
$this->photos->add($photos);
return $this;
}
/**
* Remove photos
*
* @param \VDKP\Site\BackendBundle\Entity\Photo $photos
*/
public function removePhoto(\VDKP\Site\BackendBundle\Entity\Photo $photos)
{
$this->photos->removeElement($photos);
}
/**
* Get photos
*
* @return \Doctrine\Common\Collections\Collection
*/
public function getPhotos()
{
return $this->photos;
}
Photo.php
/**
* @ORM\ManyToOne(targetEntity="Good", inversedBy="photos")
* @ORM\JoinColumn(name="good_id", referencedColumnName="id")
**/
private $good;
GoodController,updateACtion:
public function updateAction(Request $request, $id)
{
$em = $this->getDoctrine()->getManager();
$entity = $em->getRepository('VDKPSiteBackendBundle:Good')->find($id);
if (!$entity) {
throw $this->createNotFoundException('Unable to find Good entity.');
}
$originalPhotos = new \Doctrine\Common\Collections\ArrayCollection();
foreach ($entity->getPhotos() as $photo) {
$originalPhotos->add($photo);
}
$editForm = $this->createEditForm($entity);
$editForm->handleRequest($request);
if ($editForm->isValid()) {
foreach ($originalPhotos as $photo) {
if (false === $entity->getPhotos()->contains($photo)) {
$photo->setGood(null);
$em->persist($photo);
}
}
$em->persist($entity);
$em->flush();
}
return $this->redirect($this->generateUrl('good_edit', array('id' => $id)));
return array(
'entity' => $entity,
'edit_form' => $editForm->createView(),
'delete_form' => $deleteForm->createView(),
);
}
我做了文档here中所写的所有内容。
抱歉我的英文。谢谢你的帮助。
答案 0 :(得分:0)
看起来你错过了这部分文档:
foreach ($originalTags as $tag) {
if (false === $task->getTags()->contains($tag)) {
// remove the Task from the Tag
$tag->getTasks()->removeElement($task);
// if it was a many-to-one relationship, remove the relationship like this
// $tag->setTask(null);
$em->persist($tag);
// if you wanted to delete the Tag entirely, you can also do that
// $em->remove($tag);
}
}
所以,我认为你必须对你的数据类型做一些类似的事情:Good和Photo。
答案 1 :(得分:0)
我认为,文档不准确,因为:
在这部分代码中:
$originalTags = new ArrayCollection();
// Create an ArrayCollection of the current Tag objects in the database
foreach ($task->getTags() as $tag) {
$originalTags->add($tag);
}
我们收集与数据库中当前任务有关系的标签。
在这部分代码中:
foreach ($originalTags as $tag) {
if (false === $task->getTags()->contains($tag)) {
// remove the Task from the Tag
$tag->getTasks()->removeElement($task);
// if it was a many-to-one relationship, remove the relationship like this
// $tag->setTask(null);
$em->persist($tag);
// if you wanted to delete the Tag entirely, you can also do that
// $em->remove($tag);
}
}
我们必须比较$ request数据和$ originalTags数组数据。但是,我们将$ originalTags与$ task-> getTags()进行比较,这基本上是相同的。