OpenCV - 检测手绘形状

Question

OpenCV能否检测到手绘的几何形状如下？形状可以是矩形，三角形，圆形，曲线，弧形，多边形，...... 我将开发一个检测这些形状的android应用程序。

Answer 1

好吧，我在哈利试了一下。通常你需要对输入进行骨架化。无论如何。你可以根据他们的观点来推断形状。通常一个正方形有4个，三角形3个等。 努力结果：

Canny结果：

多边形近似：

控制台输出：

contour points:11
contour points:6
contour points:4 
contour points:5

以下是代码：

    Mat src=imread("WyoKM.png");
    Mat src_gray(src.size(),CV_8UC1);
    if (src.empty()) exit(-10);
    imshow("img",src);

    /// Convert image to gray and blur it
    cvtColor( src, src_gray, CV_BGR2GRAY );
    threshold(src_gray,src_gray,100,255,src_gray.type());
    imshow("img2",src_gray);

    Mat canny_output;
    vector<vector<Point> > contours;
    vector<Vec4i> hierarchy;

    /// Detect edges using canny
    int thresh=100;
    Canny( src_gray, canny_output, thresh, thresh*2, 3 );
    imshow("canny",canny_output);
    imwrite("canny.jpg",canny_output);

    /// Find contours
    findContours( canny_output, contours, hierarchy, CV_RETR_TREE, CV_CHAIN_APPROX_SIMPLE, Point(0, 0) );

    // testing the approximate polygon
    cv::Mat result(src_gray.size(),CV_8U,cv::Scalar(255));
    for(int i=0;i<contours.size();i=i+4) //for testing reasons. Skeletonize input.
    {
        std::vector<cv::Point> poly;
        poly.clear();
        cv::approxPolyDP(cv::Mat(contours[i]),poly,
            5, // accuracy of the approximation
            true); // yes it is a closed shape

        // Iterate over each segment and draw it
        std::vector<cv::Point>::const_iterator itp= poly.begin();
        cout<<"\ncontour points:"<<poly.size();
        while (itp!=(poly.end()-1)) {
            cv::line(result,*itp,*(itp+1),cv::Scalar(0),2);
            ++itp;
        }
        // last point linked to first point
        cv::line(result,
            *(poly.begin()),
            *(poly.end()-1),cv::Scalar(20),2);
    }

    imshow("result",result);
    imwrite("results.jpg",result);

    cvWaitKey();