我正在用VHDL编写Matrix Transpose的代码我在每个时钟周期以行主要和矩阵的一个元素为输入,并且我以列主格式存储数据之后我以coloumn主格式元素发送数据元素每个时钟周期到输出。代码如下所示是正确模拟,但后合成结果不对,任何人都可以帮助如何合成代码以获得正确的结果
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.numeric_std.ALL;
entity Matrix_Trans_Sysgen is
generic(n: integer :=3);
port (my_clk : in std_logic;
my_ce : in std_logic;
input_matrix : in std_logic_vector(5 downto 0);
output_matrix : out std_logic_vector(5 downto 0)
);
end Matrix_Trans_Sysgen;
architecture Behavioral of Matrix_Trans_Sysgen is
type t1 is array (natural range<>) of std_logic_vector(5 downto 0);
signal a : t1((n*n)-1 downto 0) :=(others => (others =>'0'));
signal output_there : std_logic :='0';
signal x : integer range 0 to 2*n :=0;
signal y : integer range 0 to 2*n :=0;
signal z : integer range 0 to 2*n*n :=0;
begin
----- Process to take all input_matrix into array
process(my_clk,input_matrix,x,y)
begin
if(x < n) then
if(y < n) then
if(rising_edge(my_clk)) then
a(y*n+x) <= input_matrix;
y <= y+1;
end if;
else
x<=x+1;
y<=0;
end if;
else
output_there <= '1';
end if;
end process;
----- Process to send all output elements through port
process(my_clk,z,output_there)
begin
if (output_there = '1') then
if(z < n*n) then
if(rising_edge(my_clk)) then
output_matrix <= a(z);
z<=z+1;
end if;
end if;
end if;
end process;
end Behavioral;
谢谢和问候
的Teja
答案 0 :(得分:0)
使用通常的时钟进程模板重写它。也就是说,用
“if rising_edge(clk) then ...
”
过程中最外层。综合工具寻找这个结构并正确处理它;其他形式的过程可能会混淆这些工具。