如何从mayavi中的delaunay滤镜中提取三角形?
我想像matplotlib那样提取三角形
import numpy as np
import matplotlib.delaunay as triang
from enthought.mayavi import mlab
x = np.array([0, 1, 2, 0, 1, 2, 0, 1, 2])
y = np.array([0, 0, 0, 1, 1, 1, 2, 2, 2])
z = np.zeros(9)
#matplotlib
centers, edges, triangles_index, neig = triang.delaunay(x,y)
#mayavi
vtk_source = mlab.pipeline.scalar_scatter(x, y, z, figure=False)
delaunay = mlab.pipeline.delaunay2d(vtk_source)
我想从mayavi delaunay过滤器中提取三角形以获取变量@triangle_index和@centers(就像matplotlib一样)
我唯一发现的就是这个 http://docs.enthought.com/mayavi/mayavi/auto/example_delaunay_graph.html
但只获得边缘,并且编码与matplotlib不同
答案 0 :(得分:1)
获取三角形索引:
poly = delaunay.outputs[0]
tindex = poly.polys.data.to_array().reshape(-1, 4)[:, 1:]
poly
是PolyData对象,poly.polys
是存储索引信息的CellArray对象。
有关CellArray的详细信息:http://www.vtk.org/doc/nightly/html/classvtkCellArray.html
要获得每个外接圆的中心,您需要循环每个三角形并计算中心:
centers = []
for i in xrange(poly.number_of_cells):
cell = poly.get_cell(i)
points = cell.points.to_array()[:, :-1].tolist()
center = [0, 0]
points.append(center)
cell.circumcircle(*points)
centers.append(center)
centers = np.array(centers)
cell.circumcircle()
是一个静态函数,所以你需要将三角形的所有点作为参数传递,中心数据将通过修改第四个参数返回。
以下是完整代码:
import numpy as np
from enthought.mayavi import mlab
x = np.array([0, 1, 2, 0, 1, 2, 0, 1, 2])
y = np.array([0, 0, 0, 1, 1, 1, 2, 2, 2])
z = np.zeros(9)
vtk_source = mlab.pipeline.scalar_scatter(x, y, z, figure=False)
delaunay = mlab.pipeline.delaunay2d(vtk_source)
poly = delaunay.outputs[0]
tindex = poly.polys.data.to_array().reshape(-1, 4)[:, 1:]
centers = []
for i in xrange(poly.number_of_cells):
cell = poly.get_cell(i)
points = cell.points.to_array()[:, :-1].tolist()
center = [0, 0]
points.append(center)
cell.circumcircle(*points)
centers.append(center)
centers = np.array(centers)
print centers
print tindex
输出结果为:
[[ 1.5 0.5]
[ 1.5 0.5]
[ 0.5 1.5]
[ 0.5 0.5]
[ 0.5 0.5]
[ 0.5 1.5]
[ 1.5 1.5]
[ 1.5 1.5]]
[[5 4 2]
[4 1 2]
[7 6 4]
[4 3 1]
[3 0 1]
[6 3 4]
[8 7 4]
[8 4 5]]
结果可能与matplotlib.delaunay
不同,因为有许多可能的解决方案。