我们有一个非常复杂的查询，我们使用eval（）函数来评估一些数据。
但似乎在eval（）中没有正确处理AND运算符。
例如：
if(eval('#20:34 IN out[@class='attempts'].in.@rid AND \'b\' IN out[@class='attempts'].choice'), true, false) as attempt_b
在该示例中，我们期望仅获得具有#20:34的@rid并且具有“b”的“choice”属性的数据，该属性将返回到真
“out”字段有$ current。@ rid我们的SELECT查询。
这是样本数据：
out ------ in ---- choices
14:3 ---- 20:34 ------ b
14:4 ---- 20:34 ------ a
14:7 ---- 20:34 ------ c
14:8 ---- 20:34 ------ d
例如：if(eval('#20:34 IN out[@class='attempts'].in.@rid AND \'" + choice + "\' IN out[@class='attempts'].choice'), true, false) as attempt_choice
1。）$current.@rid = #14:3 and choice is 'a'
Return Output: true
Expected output: false (since there is no #20:34 with a choice of "A" in current.@rid which is #14:3)
2。）$current.@rid = #14:3 and choice is 'b'
Return Output: true
Expected output: true
3。）$current.@rid = #14:3 and choice is 'c'
Return Output: true
Expected output: false (since there is no #20:34 with a choice of "c" in current.@rid which is #14:3)
4。）$current.@rid = #14:3 and choice is 'd'
Return Output: true
Expected output: false (since there is no #20:34 with a choice of "d" in current.@rid which is #14:3)`
我不知道这只是我们的查询问题还是在orientdb中。如果有人能引导我达到我们想要达到的目标，那将是一个很大的帮助。
答案 0 :(得分：0)
我认为这是一个引用问题：你关心逃避'b'而不是其他人。尝试类似：
if(eval("#20:34 IN out[@class='attempts'].in.@rid AND 'b' IN out[@class='attempts'].choice"), true, false) as attempt_b