分区的工作原理如下:数组中有两个索引i和j,在分区算法的最开始,我指向数组中的第一个元素,j指向最后一个元素。然后算法向前移动,直到找到值大于或等于枢轴的元素。索引j向后移动,直到找到值小于或等于枢轴的元素。如果i≤j则交换它们并且我步进到下一个位置(i + 1),j步进到前一个位置(j-1)。当i变得大于j时,算法停止。
你能看出问题是什么,因为我找不到它。非常感谢帮助。
public static int partition(int arr[], int left, int right)
{
int x = arr[right];
int i = left-1;
int temp=0;
for (int j=left; j<right; j++)
{
if(arr[j]<=x)
{
i++;
temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
}
temp = arr[i+1];
arr[i+1] = arr[right];
arr[right] = temp;
return (i+1);
}
修改
Eclipse说有两个问题,一个是在分区函数中使用这行代码:
int x = arr[right];
使用我的测试类的这一行:
sort.partition(array, 100, array.length);
这是测试类,其中包括我未提及的功能。
import java.util.Random;
public class test {
/**
* @param args
*/
public static void main(String[] args) {
int size = 1000;
int max = 5000;
int[] array = new int[size];
int loop = 0;
Random generator = new Random();
//Write a loop that generates 1000 integers and
//store them in the array using generator.nextInt(max)
generator.nextInt(max); //generating one
//I need to generate 1000
//So I need some kind of loop that will generate 1000 numbers.
for (int i =0; i<1000; i++)
{
generator.nextInt(max);
}
/**
* After I do this, I'll have the array, array.
* Then comes what's under this.
* THat method is for measuring the time.
* System.currentTimeMillis();,
* with this, I can collect a time for the start of the method
* and one for the end.
* Time at the end, minus the time at the start
* gets us the running time.
*/
long result;
long startTime = System.currentTimeMillis();
sort.quickSort(array, 100, array.length-1);
long endTime = System.currentTimeMillis();
result = endTime-startTime;
System.out.println("The quick sort runtime is " + result + " miliseconds");
long result2;
long startTime2 = System.currentTimeMillis();
sort.partition(array, 100, array.length);
long endTime2 = System.currentTimeMillis();
result2 = endTime2 - startTime2;
System.out.println("The partition runtime is "+result2 + " miliseconds");
long result3;
long startTime3 = System.currentTimeMillis();
sort.bubbleSort(array, 100);
long endTime3 = System.currentTimeMillis();
result3 = endTime3-startTime3;
System.out.println("The bubble sort runtime is "+result3 + " miliseconds");
long result4;
long startTime4 = System.currentTimeMillis();
sort.selectionSort(array, 100); //change the second number to change
//the size of an array.
long endTime4 = System.currentTimeMillis();
result4 = endTime4-startTime4;
System.out.println("The selection sort runtime is "+result4 + " miliseconds");
}
}
答案 0 :(得分:0)
首先,你实际上并没有将随机数存储在数组中,因此它将全部为零。
至于你所看到的实际错误,你有一个经典的错误。您有两个选择:make right
指向数组的末尾,或者一个指向数组的末尾。任何一个都是有效的,但你要混合两个。
具体来说,你传递1000,一个超过数组末尾的right
值,但随后你立即用它索引数组,自然会抛出异常。