Question

我收到以下SQL的错误。也许第二组眼睛可以看到问题：

错误：

1064 - 您的SQL语法出错;检查与您的MySQL服务器版本对应的手册，以便在'WHERE generation_id = 21
附近使用正确的语法在第1行限制0,25'

SQL：

SELECT * FROM data ORDER BY competition ASC, avg_monthly_searches DESC, suggested_bid DESC WHERE generation_id = 21

Answer 1

问题在于条款的顺序。 From应该出现在ORDER BY

之前

SELECT * FROM data  WHERE generation_id = 21
ORDER BY competition ASC, avg_monthly_searches DESC, suggested_bid DESC

更多信息

下面的

是MySQL中SELECT语句中的子句的顺序。你的可能只是一个错字。但是，这可以帮助某人。

SELECT
    [ALL | DISTINCT | DISTINCTROW ]
      [HIGH_PRIORITY]
      [STRAIGHT_JOIN]
      [SQL_SMALL_RESULT] [SQL_BIG_RESULT] [SQL_BUFFER_RESULT]
      [SQL_CACHE | SQL_NO_CACHE] [SQL_CALC_FOUND_ROWS]
    select_expr [, select_expr ...]
    [FROM table_references
    [WHERE where_condition]
    [GROUP BY {col_name | expr | position}
      [ASC | DESC], ... [WITH ROLLUP]]
    [HAVING where_condition]
    [ORDER BY {col_name | expr | position}
      [ASC | DESC], ...]
    [LIMIT {[offset,] row_count | row_count OFFSET offset}]
    [PROCEDURE procedure_name(argument_list)]
    [INTO OUTFILE 'file_name' export_options
      | INTO DUMPFILE 'file_name'
      | INTO var_name [, var_name]]
    [FOR UPDATE | LOCK IN SHARE MODE]]

Answer 2

导致1064错误

这个错误信息最初可能看起来很神秘。它是指向SQL Query语句中某种语法错误的一般MySQL错误。此错误可能有多种原因。

您需要更改代码，例如：

SELECT * FROM data WHERE generation_id = 21 ORDER BY competition ASC，avg_monthly_searches DESC，suggested_bid DESC

Answer 3

使用＆＃34; WHERE＆＃34;订单条款之前的条款..

所以你的代码转换为

SELECT * FROM data WHERE generation_id = 21 ORDER BY competition ASC, avg_monthly_searches DESC, suggested_bid DESC

我不确定这个SQL有什么问题

3 个答案: