如何在最后呈现游戏解决方案?

时间:2013-04-14 01:26:18

标签: java android sqlite

我使用导入的sqlite数据库将一些文本设置为我的按钮。之后我将它们洗牌,用户需要连接正确的对。游戏结束后,我想向用户提供解决方案。所以我想setText所以A1和B1按钮是一对,A2和B2是另一对,依此类推。我标记了从数据库导入的每个值,以了解哪些是对,我使用这些标记来检查正确的答案。也许这些标签可以帮助提出解决方案。这是我的代码:

public void nextQuestion() {


        TestAdapter mDbHelper = new TestAdapter(this);
        DataBaseHelper myDbHelper = new DataBaseHelper(this);

        if(!myDbHelper.checkDataBase()){
        mDbHelper.createDatabase();
        }

        try{ 

            mDbHelper.open(); 

            Cursor c = mDbHelper.getSpojnice(generateWhereClause());


            ArrayList<MyStruct> labelsA = new ArrayList<MyStruct>();
            ArrayList<MyStruct> labelsB = new ArrayList<MyStruct>();

            labelsA.add(new MyStruct(c.getString(2), "1")); // this tag should be the same to button that matches
            labelsB.add(new MyStruct(c.getString(3), "1"));
            labelsA.add(new MyStruct(c.getString(4), "2"));
            labelsB.add(new MyStruct(c.getString(5), "2"));
            labelsA.add(new MyStruct(c.getString(6), "3"));
            labelsB.add(new MyStruct(c.getString(7), "3"));
            labelsA.add(new MyStruct(c.getString(8), "4"));
            labelsB.add(new MyStruct(c.getString(9), "4"));
            labelsA.add(new MyStruct(c.getString(10), "5"));
            labelsB.add(new MyStruct(c.getString(11), "5"));


            Collections.shuffle(labelsA);
            Collections.shuffle(labelsB);


            a1.setText(labelsA.get(0).label);
            a1.setTag(labelsA.get(0).tag);
            a1.setOnClickListener(clickListener);

            b1.setText(labelsB.get(0).label);
            b1.setTag(labelsB.get(0).tag);
            b1.setOnClickListener(clickListener);

            a2.setText(labelsA.get(1).label);
            a2.setTag(labelsA.get(1).tag);
            a2.setOnClickListener(clickListener);

            b2.setText(labelsB.get(1).label);
            b2.setTag(labelsB.get(1).tag);
            b2.setOnClickListener(clickListener);

            a3.setText(labelsA.get(2).label);
            a3.setTag(labelsA.get(2).tag);
            a3.setOnClickListener(clickListener);

            b3.setText(labelsB.get(2).label);
            b3.setTag(labelsB.get(2).tag);
            b3.setOnClickListener(clickListener);
.
.
.
.
}

0 个答案:

没有答案