调用线程无法访问此对象,因为拥有其他线程

时间:2013-03-11 14:41:22

标签: c# multithreading dynamic-data-display

我正在使用DynamicDataDisplay来绘制情节。我收到一条错误消息:当调试器点击以下行时,调用线程无法访问此对象,因为其他线程拥有它

Action AddLineGraph = delegate()
{    
    timeDomainPlotter.AddLineGraph(_ods,
        new Pen(_curveColors[_statsEnableIndex[i]], 2),
        new CirclePointMarker { Size = 5, Fill = _curveColors[_statsEnableIndex[i]] },
        new PenDescription(Convert.ToString(j)));
};

this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, AddLineGraph);

我对此感到困惑,因为当我使用LineGraph绘制情节时如下:

Action AddLineGraph = delegate()
{
    timeDomainPlotter.AddLineGraph(_ods, 2, "Ch" + Convert.ToString(j) + _statsName[_statsEnableIndex[i]]);
};

this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, AddLineGraph);

运行正常。所以我想知道为什么绘图点标记会给出错误信息?感谢。

编辑:我在_curveColors定义的地方添加了更多编码。

public void InitiatePlot()
{
//  InitializeComponent();

    //   timeDomainPlotter.Legend.Remove();

    _initialChildrenCount = timeDomainPlotter.Children.Count;

    int count = timeDomainPlotter.Children.Count;

    //do not remove the initial children
    if (count > _initialChildrenCount)
    {
        for (int i = count - 1; i >= _initialChildrenCount; i--)
        {
            timeDomainPlotter.Children.RemoveAt(i);
        }
    }


//  _curveColors = new System.Drawing.Color[_nMaxStatsPerChannel];
    _curveColors = new Brush[_nMaxStatsPerChannel];


    for (int i = 0; i < _nMaxStatsPerChannel; i++)
    {

        _curveColors[i] = new SolidColorBrush((Color)ColorConverter.ConvertFromString(_colorList[i]));
    // _curveColors[i] = System.Drawing.Color.FromName(_colorList[i]);

    }

    _statsName = Enum.GetNames(typeof(Window1.ROISignalList));


    //_statsEnableIndex = new int[_nActiveStatsPerChannel];
    for (int j = 0; j < _nActiveChannels; j++)  // init data source structure
    {
    // count = 0;
        for (int i = 0; i < _nActiveStatsPerChannel; i++)
        {

            _ods = new ObservableDataSource<Point>();
            _odsAll[j * _nActiveStatsPerChannel + i] = _ods;   // _osdAll: C0S0 C0S1 C0S2 C1S0 C1S1 C1S2 ... C4S0 C4S1 C4S2


            Action AddLineGraph = delegate()
        {

            timeDomainPlotter.AddLineGraph(_ods,
                    new Pen(_curveColors[_statsEnableIndex[i]], 2),
                    new CirclePointMarker { Size = 5, Fill = _curveColors[_statsEnableIndex[i]] },
                    new PenDescription(Convert.ToString(j)));
        };
        this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, AddLineGraph);

        }
    }
}

我找到了原因。正如SpaceghostAli提到的那样,_curveColors确实是导致此错误的罪魁祸首。

我不得不说我没有完全找出原因,但是如果我用定义的颜色替换所有的_curveColors,问题就消失了。特别是,这里是给出错误的代码:

Action AddLineGraph = delegate()
{

    timeDomainPlotter.AddLineGraph(_ods,
        new Pen(_curveColors[_statsEnableIndex[i]], 2),
        new CirclePointMarker { Size = 5, Fill = _curveColors[_statsEnableIndex[i]] },
        new PenDescription(Convert.ToString(j)));
};

this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, AddLineGraph);

这里是没有错误的代码:

Action AddLineGraph = delegate()
{

    timeDomainPlotter.AddLineGraph(_ods,
        //new Pen(_curveColors[_statsEnableIndex[i]], 2),
        new Pen( new SolidColorBrush(Colors.Transparent), 2),
        new CirclePointMarker { Size = 5, Fill = new SolidColorBrush(Colors.Green) },
        new PenDescription(Convert.ToString(j)));
};

this.Dispatcher.Invoke(System.Windows.Threading.DispatcherPriority.Normal, AddLineGraph);

您只能看到_curveColors被更改为确定性颜色。

1 个答案:

答案 0 :(得分:2)

我猜测_curveColors并没有在UI线程上创建。您应该追溯并查看如何调用InitiatePlot并确保UI线程拥有_curveColors。