Question

我正在尝试用Java编写一个简单的游戏，使用2D阵列创建一个点网格，供用户继续使用。我已经做到了这一点，我已经达到了我要求用户选择移动的地步，然而，在那之后，我想重新打印网格，其旧空间为空，并且“o”在他们搬到的空间。我不确定如何重新打印网格，因为当我第一次打印它时，我使用了一个if语句告诉循环哪里不放点。我将在下面发布代码，非常感谢提示！

import java.util.Scanner;
import java.util.Random;
public class main {

/**
 * @param args
 */
public static void main(String[] args) {
    // TODO Auto-generated method stub

    char[][] gridArray = new char[10][10];
    int randomRow;
    int randomCol;
    int randomRow2;
    int randomCol2;
    String moveSelect;
    boolean validInput = true;

    int min = 0;
    int max = 9;

    Random tRNG = new Random();
    randomRow = tRNG.nextInt(max - min + 1) + min;
    randomCol = tRNG.nextInt(max - min + 1) + min;
    randomRow2 = tRNG.nextInt(max - min + 1) + min;
    randomCol2 = tRNG.nextInt(max - min + 1) + min;

    gridArray[randomRow][randomCol] = 'o';
    gridArray[randomRow2][randomCol2] = 'X';

    for (int i = 0; i < gridArray.length; i++)
    {
        for (int j = 0; j < gridArray.length; j++)
        {       
            if (gridArray[i][j] != gridArray[randomRow][randomCol] && gridArray[i][j] != gridArray[randomRow2][randomCol2])
            {
                gridArray[i][j] = '.';
            }
            System.out.print(gridArray[i][j]);
        }
        System.out.println("");  
    }

    System.out.println("Enter a movement choice W A S or D");
    do{

        Scanner keyboard = new Scanner(System.in);
        moveSelect = keyboard.nextLine();

        if ( moveSelect.equals("w"))
        {
            gridArray[randomRow][randomCol] = gridArray[randomRow+1][randomCol];
            gridArray[randomRow][randomCol] = ' ';
            validInput = true;      
        }

        else if ( moveSelect.equals("a"))
        {
            gridArray[randomRow][randomCol] = gridArray[randomRow][randomCol-1];
            gridArray[randomRow][randomCol] = ' ';
            validInput = true;
        }

        else if ( moveSelect.equals("s"))
        {
            gridArray[randomRow][randomCol] = gridArray[randomRow-1][randomCol];
            gridArray[randomRow][randomCol] = ' ';
            validInput = true;
        }

        else if (moveSelect.equals("d"))
        {
            gridArray[randomRow][randomCol] = gridArray[randomRow][randomCol+1];
            gridArray[randomRow][randomCol] = ' ';
            validInput = true;
        }

        else
        {
            System.out.println("Invalid Entry. Try again.");
            validInput = false;
        }

    } while (validInput == false);
}

}

Answer 1

我认为大多数问题都来自对数组的一般混淆。例如。当您按下w：

时，代码块中的行会运行

gridArray[randomRow][randomCol] = gridArray[randomRow+1][randomCol];

将randomRow，randomCol（在本例中为'x'）的数组的char值设置为randomRow + 1，randomCol下面一行下方数组空间的char值。然后是代码行：

gridArray[randomRow][randomCol] = ' ';

为同一个空间分配一个新值，使上面的代码变得毫无价值！最后，randomRow和randomCol永远不会被修改。（也有一些关于x将以更高的行值移动的方式的混淆）

您在此代码块中实际需要做的就是：

randomRow -= 1;

之后，您可以使用之前的打印代码重新打印整个网格。虽然此代码还存在其他问题，但这些问题远非最佳。还有一个类似的问题，即for循环中的if语句有效，但后来导致了问题。简单地重写它来解决所有错误的问题，你得到这个：

char[][] gridArray = new char[10][10];
int randomRow;
int randomCol;
int randomRow2;
int randomCol2;
String moveSelect;
boolean validInput = true;

int min = 0;
int max = 9;

Random tRNG = new Random();
randomRow = tRNG.nextInt(max - min + 1) + min;
randomCol = tRNG.nextInt(max - min + 1) + min;
randomRow2 = tRNG.nextInt(max - min + 1) + min;
randomCol2 = tRNG.nextInt(max - min + 1) + min;

gridArray[randomRow][randomCol] = 'o';
gridArray[randomRow2][randomCol2] = 'X';

for (int i = 0; i < gridArray.length; i++)
{
    for (int j = 0; j < gridArray.length; j++)
    {       
        if (!((i == randomRow && j == randomCol) || (i == randomRow2 &&  j == randomCol2)))
        {
            gridArray[i][j] = '.';
        }
        System.out.print(gridArray[i][j]);
    }
    System.out.println("");  
}

System.out.println("Enter a movement choice W A S or D");
do{

    Scanner keyboard = new Scanner(System.in);
    moveSelect = keyboard.nextLine();

    if ( moveSelect.equals("w"))
    {
        randomRow -= 1;
        validInput = true;      
    }

    else if ( moveSelect.equals("a"))
    {
        randomCol -= 1;
        validInput = true;
    }

    else if ( moveSelect.equals("s"))
    {
        randomRow += 1;
        validInput = true;
    }

    else if (moveSelect.equals("d"))
    {
        randomCol -= 1;
        validInput = true;
    }

    else
    {
        System.out.println("Invalid Entry. Try again.");
        validInput = false;
    }

} while (validInput == false);
gridArray[randomRow][randomCol] = 'o';
gridArray[randomRow2][randomCol2] = 'X';

for (int i = 0; i < gridArray.length; i++)
{
    for (int j = 0; j < gridArray.length; j++)
    {       
        if (!((i == randomRow && j == randomCol) || (i == randomRow2 &&  j == randomCol2)))
        {
            gridArray[i][j] = '.';
        }
        System.out.print(gridArray[i][j]);
    }
    System.out.println("");  
}

Answer 2

如果validInput == true

，请创建一个打印网格的方法

public static void printGrid(char[][]gridArray){
    for (int i = 0; i < gridArray.length; i++)
    {
        for (int j = 0; j < gridArray.length; j++)
        {       
            System.out.print(gridArray[i][j]);
        }
        System.out.println("");  
    }
}

我将gridArray [randomRow] [randomCol]从=''修改为='。'因为你想让它成为一个点吗？（如果你真的想让它成为一个空间，那么就像它已经存在一样）要进行验证，请将每个方向更改为：

if ( moveSelect.equals("w")&&randomRow!=0)
        {
            gridArray[randomRow][randomCol] = gridArray[randomRow-1][randomCol];
            gridArray[randomRow][randomCol] = '.';
            validInput = true;      
        }

在do结束时，

if(validInput) printGrid(gridArray);

简单的2d阵列java游戏

2 个答案: