2D数组游戏板... NullPointerException

时间:2013-11-15 07:44:52

标签: java arrays

我需要制作一个棋盘游戏,我从阵列的左下角开始[3] [0]“Ursa Major”。当我向“西”移动时,我得到一个NullPointerException。我还需要一些帮助对角移动到[2] [1]“northeast”,但不知道如何为它编写代码。任何帮助将不胜感激。

    //Declare Variables
    Map map;
    String input;
    Scanner scan;
    int row, col;

    //Initialize Varibales
    map = new Map();
    scan = new Scanner(System.in);
    row = 3; col = 0;

    //Begin user dialog
    System.out.println("Welcome to the Great Cal Poly Underground");
    input ="";
    while(!input.equals("quit"))
    {
       System.out.println(map.rooms[row][col].name);
       System.out.print(">");
       input = scan.nextLine().toLowerCase();

       if (input.equals("w"))
       {   if(map.rooms[row][col].isValidExit("w"))
           col--;
           else
           System.out.println("You cant go that way");
       }
       else
       if (input.equals("e"))
       {   if(map.rooms[row][col].isValidExit("e"))
           col++;
           else
           System.out.println("You cant go that way");
       }

这是我的用户界面,这是我的地图

 Room[][] rooms = new Room[4][4];

Map()
{
   Room lectureHall = new Room();
   Room cafeteria = new Room();

   lectureHall.name  = "Ursa Major";
   lectureHall.exits = new String []{"e"};//can add north south west

   cafeteria.name  = "Los Olivos";
   cafeteria.exits = new String []{"w"}; // can add north south east

   rooms[3][0] = lectureHall;
   rooms[2][1] = cafeteria;

这是我的房间

boolean isValidExit(String anExit)
{
    boolean result = false;
    int index = 0;
    while (result == false && index < exits.length)
    {
        if(exits[index].equals(anExit))
            result = true;
        index++;
    }     
    return result;

3 个答案:

答案 0 :(得分:2)

rooms有16个引用,但只设置了两个(rooms[3][0] = lectureHall; rooms[2][1] = cafeteria;)。您需要为其余索引创建对象。

答案 1 :(得分:1)

用Java初始化数组:

Room[][] rooms = new Room[4][4];

仅初始化rooms数组,这意味着只有数组不能为空。

但是,任何“内部”对象都没有初始化。

如果您希望热切地创建房间然后设置其属性,请执行以下操作:

Room[][] rooms = new Room[4][4];

for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
        rooms[i][j] = new Room(...);
    }
}

答案 2 :(得分:0)

考虑上面的所有答案,,你的起始单元格是房间[3] [0],如果你想要“西”,你就是递减col变量:

if (input.equals("w"))
{   if(map.rooms[row][col].isValidExit("w"))
    //you are decrementing col, which will become -1 after decrementing
    col--;
    else
       System.out.println("You cant go that way");
}

然后程序在循环中返回到开头,在那里显示当前房间的名称:

while(!input.equals("quit"))
{
   System.out.println(map.rooms[row][col].name);
   System.out.print(">");

并且由于col = -1,你正在尝试map.rooms [3] [ - 1] ,这肯定会导致异常。

确保您没有引用&lt; 0