示例:
import com.google.gson.Gson;
class GsonDemo {
private static class Static {String key = "static";}
private class NotStatic {String key = "not static";}
void testGson() {
Gson gson = new Gson();
System.out.println(gson.toJson(new Static()));
// expected = actual: {"key":"static"}
System.out.println(gson.toJson(new NotStatic()));
// expected = actual: {"key":"not static"}
class MethodLocal {String key = "method local";}
System.out.println(gson.toJson(new MethodLocal()));
// expected: {"key":"method local"}
// actual: null (be aware: the String "null")
Object extendsObject = new Object() {String key = "extends Object";};
System.out.println(gson.toJson(extendsObject));
// expected: {"key":"extends Object"}
// actual: null (be aware: the String "null")
}
public static void main(String... arguments) {
new GsonDemo().testGson();
}
}
我希望这些序列化特别是在单元测试中。有办法吗? 我找到了Serializing anonymous classes with Gson,但论证只适用于反序列化。
答案 0 :(得分:1)
FWIW,Jackson会很好地序列化匿名和本地类。
public static void main(String[] args) throws Exception
{
ObjectMapper mapper = new ObjectMapper();
class MethodLocal {public String key = "method local";}
System.out.println(mapper.writeValueAsString(new MethodLocal()));
// {"key":"method local"}
Object extendsObject = new Object() {public String key = "extends Object";};
System.out.println(mapper.writeValueAsString(extendsObject));
// {"key":"extends Object"}
}
请注意,默认情况下,Jackson不会像Gson那样通过反射访问非公共字段,但可以配置为执行此操作。 Jackson的方法是使用常规Java属性(通过get / set方法)。 (将其配置为使用私有字段确实会降低运行时性能,但它仍然比Gson快。)