Question

我使用GSON序列化POJO - 改变之前和之后的对象。

由Struts2设置的改变版（称为A）可以很容易地序列化为Json。

虽然通过iBatis（称为B）从数据库获取的更改前的POJO无法序列化。

错误消息显示：忘记注册类型适配器？

我已阅读Gson API。但我不认为为每个POJO注册一个类型适配器是一个好主意。什么使B无法序列化？

我为我的POJO编写了一个clone（），也可以完成从B克隆的对象。

这令人困惑......有人能回答我吗？

在改变之前（B的克隆）：

{"id":"6429B5329C544711A9848AF243D10E4E","idType":"未选择","firstDate":"Feb 29, 2012 12:00:00 AM","name":"testetes","gender":"男","phone":"553223","city":"未选择","ocup":"未选择","nation":"未选择","famStru":"未选择","infSouc":"未选择","creater":"EE4783A6272A4B62A5CC68DB3C11FE1E","createDate":"Feb 29, 2012 12:00:00 AM","purpose":"未选择","education":"未选择","income":"未选择","cars":"未选择","acptCarpRent":"未选择","acptCarpPrice":"未选择","handStand":"未选择","intentHouse":"未选择","intentArea":"未选择","intentLayout":"未选择","nextDate":"Mar 7, 2012 12:00:00 AM","wuyeType":"未选择","attentionPro":"958B9E093A84415B901900C2DA25C712","ordinaryTraffic":"未选择","attentionPoint":"未选择","buyDate":"未选择","cityArea":"未选择","lastUpdate":"Feb 29, 2012 12:00:00 AM","lastModifier":"EE4783A6272A4B62A5CC68DB3C11FE1E","saler":"A4FB4877DC2945E980477544A955B57F","state":"意向","status":"0"}

改变后（A）：

{"id":"6429B5329C544711A9848AF243D10E4E","idType":"未选择","firstDate":"Feb 29, 2012 12:00:00 AM","visitMode":"","name":"testetes","gender":"男","telPhone":"","phone":"553223","fax":"","adrs":"","postCode":"","email":"","workUnit":"","city":"未选择","media_id":"","ocup":"未选择","idNum":"","nation":"未选择","famStru":"未选择","infSouc":"未选择","createDate":"Feb 29, 2012 12:00:00 AM","idAdr":"","purpose":"未选择","education":"未选择","income":"未选择","cars":"未选择","acptCarpRent":"未选择","acptCarpPrice":"未选择","handStand":"未选择","intentHouse":"未选择","intentArea":"未选择","intentLayout":"未选择","customerDetail":"","wuyeType":"未选择","attentionPro":"958B9E093A84415B901900C2DA25C712","ordinaryTraffic":"未选择","attentionPoint":"未选择","buyDate":"未选择","cityArea":"未选择","lastUpdate":"Mar 11, 2012 2:58:04 PM","lastModifier":"00000000000000000000000000000000","saler":"A4FB4877DC2945E980477544A955B57F","state":"意向"}

Answer 1

听起来您的POJO属于Customer类型？当你克隆你的对象时，你正在创建一个新的Customer，而Gson可以很好地序列化它。但是，从DB获取同一对象时，它不是标准的Customer对象。相反，它是一个包含一些持久性信息的子类，例如对象的类。

可能最简单的解决方案是使用Gson的@Expose注释。如果使用new GsonBuilder().excludeFieldsWithoutExposeAnnotation().create()创建Gson对象，则可以使用@Expose标记要序列化的每个Customer字段。

，任何其他字段，包括持久性框架子类的字段，都不会被序列化。

Answer 2

布兰登是对的。如果您不想使用任何注释或修改POJO类，这是另一种解决方案。这对任何其他人都有帮助。

Type typeOfSrc = new TypeToken<A>() {}.getType(); //this helps for generic one.
gson.toJson(obj, typeOfSrc); or gson.toJson(obj, A.class);

使用Gson序列化POJO

2 个答案: