使用类继承创建模板类型的实例

时间:2013-02-10 13:16:29

标签: c# templates inheritance activator

我有一个我似乎无法解决的问题。

假设我的课程设置如下:

public abstract class GenericCustomerInformation
{
    //abstract methods declared here
}

public class Emails : GenericCustomerInformation
{
    //some new stuff, and also overriding methods from GenericCustomerInformation
}

public class PhoneNumber : GenericCustomerInformation
{
    //some new stuff, and also overriding methods from GenericCustomerInformation
}

现在假设我有这样的功能设置:

private void CallCustomerSubInformationDialog<T>(int iMode, T iCustomerInformationObject)
{
    //where T is either Emails or PhoneNumber

    GenericCustomerInformation genericInfoItem;

    //This is what I want to do:
    genericInfoItem = new Type(T);

    //Or, another way to look at it:
    genericInfoItem = Activator.CreateInstance<T>(); //Again, does not compile
}

CallCustomerSubInformationDialog<T>函数中,我有一个基类型GenericCustomerInformation的变量,我希望用T中的任何一个来实例化它(其中一个派生类型:{ {1}}或Emails

一个简单的事情是使用一堆PhoneNumber条件,但我不想做任何有条件的事情,因为这将使我的代码比它需要的大得多..

1 个答案:

答案 0 :(得分:1)

这样的事可能吗? (或者我误解了?)

private void CallCustomerSubInformationDialog<T>(int iMode, T iCustomerInformationObject) where T: GenericCustomerInformation, new()
{
    //where T is either Emails or PhoneNumber
    GenericCustomerInformation genericInfoItem;
    //This is what you could try to do:
    genericInfoItem = new T();

}

注意:注意T ...的限制