我正在使用MS SQL SERVER 2008,我有以下数据:
select * from account;
| PERIOD | ACCOUNT | VALUE |
----------------------------
| 2000 | Asset | 205 |
| 2000 | Equity | 365 |
| 2000 | Profit | 524 |
| 2001 | Asset | 142 |
| 2001 | Equity | 214 |
| 2001 | Profit | 421 |
| 2002 | Asset | 421 |
| 2002 | Equity | 163 |
| 2002 | Profit | 325 |
我想让它们成为这样:
| ACCOUNT | 2000 | 2001 | 2002 |
--------------------------------
| Asset | 205 | 142 | 421 |
| Equity | 365 | 214 | 163 |
| Profit | 524 | 421 | 325 |
我尝试查询使用pivot query
,但该值必须使用aggregate function
,结果不合适。我该怎么办?
答案 0 :(得分:40)
SELECT *
FROM
(
SELECT [Period], [Account], [Value]
FROM TableName
) AS source
PIVOT
(
MAX([Value])
FOR [Period] IN ([2000], [2001], [2002])
) as pvt
另一种方式,
SELECT ACCOUNT,
MAX(CASE WHEN Period = '2000' THEN Value ELSE NULL END) [2000],
MAX(CASE WHEN Period = '2001' THEN Value ELSE NULL END) [2001],
MAX(CASE WHEN Period = '2002' THEN Value ELSE NULL END) [2002]
FROM tableName
GROUP BY Account
答案 1 :(得分:6)
同时检查一下:使用xml path
和pivot
<强> SQLFIDDLE DEMO 强>
| ACCOUNT | 2000 | 2001 | 2002 |
--------------------------------
| Asset | 205 | 142 | 421 |
| Equity | 365 | 214 | 163 |
| Profit | 524 | 421 | 325 |
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
SET @cols = STUFF((SELECT distinct ',' + QUOTENAME(c.period)
FROM demo c
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT account, ' + @cols + ' from
(
select account
, value
, period
from demo
) x
pivot
(
max(value)
for period in (' + @cols + ')
) p '
execute(@query)