Question

我有一张带有“代码”和“描述”列的表。行应动态转置为列例如

Create Table #table(Code Varchar(15), Code_Desc Varchar(30))

Insert Into #table Values('T01', 'Desc1') 
Insert Into #table Values('T02', 'Desc2')
Insert Into #table Values('T03', 'Desc3')
Insert Into #table Values('T04', 'Desc4')

Select * from #table 

Code    Code_Desc 
T01 Desc1
T02 Desc2
T03 Desc3
T04 Desc4

预期输出为：

Code    T01 T02 T03 T04 
Code_Desc Desc1 Desc2   Desc3   Desc4

谢谢

Answer 1

您可以在下面尝试

DEMO

select 'Code_Desc' as code,[T01], [T02], [T03], [T04] from #table
   pivot(max(Code_Desc) for code in ([T01], [T02], [T03], [T04]))pv

输出：

code        T01      T02    T03     T04
Code_Desc   Desc1   Desc2   Desc3   Desc4

对于动态数据透视，您可以尝试以下操作：

declare @sql varchar(max)='',@col_list varchar(8000)=''

set @col_list = (select distinct quotename([Code])+',' from #table
for xml path(''))

set @col_list = left (@col_list,len(@col_list)-1)

set @sql = 'select '+@col_list+' from
#table
pivot (max([Code_Desc]) for [Code] in ('+@col_list+'))pv'

exec(@sql)

Answer 2

如果不进行汇总，就无法实现PIVOT。

CREATE TABLE #table1
(
    TEST_NAME VARCHAR(10),
    SBNO VARCHAR(10),
    VAL VARCHAR(10)
);

INSERT INTO #table1 (TEST_NAME, SBNO, VAL)
VALUES ('Test1' ,'1', '0.304'),
       ('Test1' ,'2', '0.31'),
       ('Test1' ,'3', '0.306'),
       ('Test2' ,'1', '2.3'),
       ('Test2' ,'2', '2.5'),
       ('Test2' ,'3', '2.4'),
       ('Test3' ,'1', 'PASS'),
       ('Test3' ,'2', 'PASS')

WITH T AS
(
    SELECT SBNO, VAL, TEST_NAME    
      FROM #table1
) 
SELECT *
  FROM T
 PIVOT (MAX(VAL) FOR TEST_NAME IN([Test1], [Test2], [Test3])) P

Answer 3

不使用聚合函数进行透视

Create Table #table(Code Varchar(15), Code_Desc Varchar(30))    
Insert Into #table Values('T01', 'Desc1') 
Insert Into #table Values('T02', 'Desc2')
Insert Into #table Values('T03', 'Desc3')
Insert Into #table Values('T04', 'Desc4')        

SELECT DISTINCT dt.Code,T01,T02,T03,T04 
FROM #table 
CROSS APPLY ( VALUES ('Code_Desc','Desc1','Desc2','Desc3','Desc4'  ) ) dt (Code,T01,T02,T03,T04)

动态Sql方法

DECLARE @SQL Nvarchar(max)
        ,@Columns nvarchar(max)
        ,@Columns2 nvarchar(max)
        ,@Columns3 nvarchar(max)

SELECT @Columns =STUFF((SELECT ', '+''''+ Code_Desc+'''' FROM #table FOR XML PATH ('')),1,1,'')
SELECT @Columns2=STUFF((SELECT ', '+ Code FROM #table FOR XML PATH ('')),1,1,'')
SELECT @Columns3=STUFF((SELECT ', '+ 'dt.'+QUOTENAME(Code) FROM #table FOR XML PATH ('')),1,1,'')


SET @SQL='SELECT DISTINCT dt.[Code],'+@Columns3+'
FROM #table
CROSS APPLY (VALUES(''Code_Desc'','+@Columns+'))'+CHAR(13)+CHAR(10)+' dt( Code,'+@Columns2+')'

PRINT @SQL
EXEC (@SQL)

结果

Code        T01     T02     T03     T04
-------------------------------------------
Code_Desc   Desc1   Desc2   Desc3   Desc4

在SQL Server中没有聚合功能的PIVOT

3 个答案: