这是我的MSSQL 2008 [ERROR CODE]表的一部分,我想将其转换为以下结构。我尝试搜索解决方法,但找不到完成任务的解决方案。使用Pivot我认为不可行,因为我不能使用聚合函数。有人可以帮我解决这个问题吗?
+----------+-------+---------------------------------------------------+
| SKILL ID | SKILL | PARAMETER |
+----------+-------+---------------------------------------------------+
| 1 | 121 | STANDARD VERBIAGE & PROCEDURES |
| 1 | 121 | ISSUE IDENTIFICATION |
| 1 | 121 | CALL COURTESY |
| 1 | 121 | ISSUE RESOLUTION |
| 2 | BO | COLLECTION PROCESS ADHERENCE |
| 2 | BO | INTELLIGENCE PARAMETER |
| 3 | EM | SOFT SKILLS |
| 3 | EM | PRODUCT KNOWLEDGE |
| 3 | EM | CALL CLOSING |
| 3 | EM | CALL OPENING |
| 4 | FLC | RESOLUTION |
| 4 | FLC | NONE |
| 5 | FTA | OTHERS |
| 5 | FTA | HYGIENE FACTORS |
| 5 | FTA | ACCOUNT SCREEN |
| 5 | FTA | ORDER , DOCUMENTATION AND CONFIGURATION |
| 5 | FTA | VALIDATION SCREEN |
| 5 | FTA | PARTY SCREEN |
| 5 | FTA | ORDER , DOCUMENTATION AND CONFIGURATION |
| 6 | NCE | COMPLIANCE |
| 6 | NCE | CRM |
| 6 | NCE | ACCOUNT LEVEL /INSTALLATION DETAILS CONFIRTMATION |
| 6 | NCE | CONTENTS/BILL DETAILS |
| 6 | NCE | SELFCARE |
| 6 | NCE | FEEDBACK/SATISFACTION |
| 6 | NCE | OBJECTION RESOLUTION |
| 6 | NCE | CUSTOMER HANDLING |
| 6 | NCE | RED ALERT |
| 7 | RTO | ZERO TOLERANCE |
| 7 | RTO | OVERALL IMPRESSION |
| 7 | RTO | SUMMARY AND CLOSING |
| 7 | RTO | PROCESS KNOWLEDGE |
| 7 | RTO | OPENING |
| 8 | SHMNP | SKILL AREA |
| 8 | SHMNP | CONVINCING SKILLS |
+----------+-------+---------------------------------------------------+
这可能是预期的输出
+-------+--------------------------------+------------------------+---------------------------------------------------+
| SKILL | PARAMETER1 | PARAMETER2 | PARAMETER3 |
+-------+--------------------------------+------------------------+---------------------------------------------------+
| 121 | STANDARD VERBIAGE & PROCEDURES | ISSUE IDENTIFICATION | CALL COURTESY |
| BO | COLLECTION PROCESS ADHERENCE | INTELLIGENCE PARAMETER | NULL |
| EM | SOFT SKILLS | PRODUCT KNOWLEDGE | CALL CLOSING |
| FLC | RESOLUTION | NONE | NULL |
| FTA | OTHERS | HYGIENE FACTORS | ACCOUNT SCREEN |
| NCE | COMPLIANCE | CRM | ACCOUNT LEVEL /INSTALLATION DETAILS CONFIRTMATION |
| RTO | ZERO TOLERANCE | OVERALL IMPRESSION | SUMMARY AND CLOSING |
| SHMNP | SKILL AREA | CONVINCING SKILLS | NULL |
+-------+--------------------------------+------------------------+---------------------------------------------------+
答案 0 :(得分:11)
您可以使用PIVOT功能获得结果,您只需使用row_number()
来提供帮助。
对此的基本查询将是:
select skill_id, skill, parameter,
row_number() over(partition by skill, skill_id order by skill_id) rn
from yt;
见SQL Fiddle with Demo。我使用row_number()
为skill
和skill_id
中的每一行应用不同的值,然后您将使用此行号值作为PIVOT的列。
应用PIVOT的完整代码将是:
select skill_id, skill,[Parameter_1], [Parameter_2], [Parameter_3]
from
(
select skill_id, skill, parameter,
'Parameter_'+cast(row_number() over(partition by skill, skill_id
order by skill_id) as varchar(10)) rn
from yt
) d
pivot
(
max(parameter)
for rn in ([Parameter_1], [Parameter_2], [Parameter_3])
) piv;
在您的情况下,您似乎每种技能都有未知数量的参数。如果这是真的,那么您将需要使用动态SQL来获得结果:
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT distinct ',' + QUOTENAME('Parameter_'
+cast(row_number() over(partition by skill, skill_id
order by skill_id) as varchar(10)))
from yt
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT skill_id, skill,' + @cols + ' from
(
select skill_id, skill, parameter,
''Parameter_''+cast(row_number() over(partition by skill, skill_id
order by skill_id) as varchar(10)) rn
from yt
) x
pivot
(
max(parameter)
for rn in (' + @cols + ')
) p '
execute(@query);