Question

我正在尝试使用Python创建一个RFCOMM服务器进程，无需配对即可使用。最初，我从PyBluez文档中获取了两个示例脚本：

服务器：

# file: rfcomm-server.py

# auth: Albert Huang <albert@csail.mit.edu>
# desc: simple demonstration of a server application that uses RFCOMM sockets
#
# $Id: rfcomm-server.py 518 2007-08-10 07:20:07Z albert $

from bluetooth import *

server_sock=BluetoothSocket( RFCOMM )
server_sock.bind(("",PORT_ANY))
server_sock.listen(1)

port = server_sock.getsockname()[1]

uuid = "94f39d29-7d6d-437d-973b-fba39e49d4ee"

advertise_service( server_sock, "SampleServer",
                   service_id = uuid,
                   service_classes = [ uuid, SERIAL_PORT_CLASS ],
                   profiles = [ SERIAL_PORT_PROFILE ], 
#                   protocols = [ OBEX_UUID ] 
                    )

print "Waiting for connection on RFCOMM channel %d" % port

client_sock, client_info = server_sock.accept()
print "Accepted connection from ", client_info

try:
    while True:
        data = client_sock.recv(1024)
        if len(data) == 0: break
        print "received [%s]" % data
except IOError:
    pass

print "disconnected"

client_sock.close()
server_sock.close()
print "all done"

客户端：

# file: rfcomm-client.py
# auth: Albert Huang <albert@csail.mit.edu>
# desc: simple demonstration of a client application that uses RFCOMM sockets
#       intended for use with rfcomm-server
#
# $Id: rfcomm-client.py 424 2006-08-24 03:35:54Z albert $

from bluetooth import *
import sys

addr = None

if len(sys.argv) < 2:
    print "no device specified.  Searching all nearby bluetooth devices for"
    print "the SampleServer service"
else:
    addr = sys.argv[1]
    print "Searching for SampleServer on %s" % addr

# search for the SampleServer service
uuid = "94f39d29-7d6d-437d-973b-fba39e49d4ee"
service_matches = find_service( uuid = uuid, address = addr )

if len(service_matches) == 0:
    print "couldn't find the SampleServer service =("
    sys.exit(0)

first_match = service_matches[0]
port = first_match["port"]
name = first_match["name"]
host = first_match["host"]

print "connecting to \"%s\" on %s" % (name, host)

# Create the client socket
sock=BluetoothSocket( RFCOMM )
sock.connect((host, port))

print "connected.  type stuff"
while True:
    data = raw_input()
    if len(data) == 0: break
    sock.send(data)

sock.close()

当我在Windows上运行服务器脚本时，一切都按照我的希望进行 - 不需要配对。在这个阶段，一切都看起来很有希望。

但是，我需要服务器进程在Debian Squeeze下运行。当我在Debian上测试时，客户端连接被拒绝。在syslog中，有来自bluetoothd的消息，用于链接密钥请求失败和PIN请求。

版本信息：

PyBluez 0.18
Python 2.6
Bluez 4.66
连接两端的蓝牙v2.0硬件

This discussion似乎暗示如果我可以调整服务器套接字上的安全级别，那么配对将被禁用，一切都将按预期工作。我不清楚如何用PyBluez做到这一点，或者即使它是可能的。

我已尝试使用各种BT_SECURITY *常量调用setsockopt（），以及获取最后一个PyBluez并调用setl2capsecurity（）但未能取得任何进展。

使用PyBluez可以实现这个目标吗？

Answer 1

这是Debian Squeeze bluez默认配置的问题。

如果有其他人遇到此问题，请通过编辑/etc/bluetooth/main.conf来禁用pnat插件：

DisablePlugins = pnat

然后重新启动bluetoothd。

$ sudo invoke-rc.d bluetooth restart

PyBluez代码无需更改。

RFCOMM没有在Debian上使用PyBluez配对？

1 个答案: