Question

我在select sql语句中需要帮助。

在我的mysql数据库中：

位置表

serialID(AI)|locations | telephone | address
---------------------------------------------
1           | A       
2           | B
3           | C
4           | D

users table
userID | location chosen
-------------------------
1      | A
2      | B
3      | B

我想计算选择特定位置并在表格中显示的人数。因此，如果此特定位置有更多用户选择作为他们最喜欢的位置，它将向上移动到第一行。我可以知道我该怎么办？

当它填充到动态表格中时会出现类似的情况 - ＆gt;

location | address | telephone | user's favourable
B        |  -      | -         |  2
A        |  -      | -         |  1
C        |  -      | -         |  0
D        |   -     | -         |  0

Answer 1

你可以这样做一个查询：

SELECT l.locations, l.telephone, l.address, COUNT (u.userID) as `location_count`
FROM location AS l
LEFT OUTER JOIN users AS u on l.locations = u.location_chosen
GROUP BY l.locations
ORDER BY `location_count` DESC

Answer 2

SELECT  loc.*, countResult.usersFavourable
FROM    location loc
        LEFT JOIN
        (
            SELECT  locationChoosen, COUNT(*) `usersFavourable`
            FROM    users
            GROUP BY    locationChoosen
        ) countResult ON loc.locations = countResult.locationChoosen
ORDER BY countResult.usersFavourable DESC, loc.locations

Answer 3

尝试这样的事情：

SELECT  l.location, l.address, l.telephone, COUNT(u.userID) AS [users favourable]
FROM    location l
        LEFT JOIN
            users u
            ON l.location = u.locationchosen
GROUP BY l.location, l.address, l.telephone

Answer 4

使用它：

select count(userId) count,locations,address,telephone 
from Table1 Left join Table2 
on Table1.locations = Table2.location

group by locations order by count desc ;

见这里.. link

Answer 5

 SELECT LocationChosen, Count(*) FROM usersTable GROUP BY LocationChosen

如何计算选择特定位置的人数？

5 个答案: