Question

我正在开发一个拥有多个代理和成员的项目。现在我必须执行以下操作（通过SQL查询）：

选择已完成付款的母代理商下的代理商和会员（总数为430，即130 + 150 + 150），为期3个月。
每个代理商都有n个成员，因此对于每个代理商，我需要检查所有成员是否支付了3个月的会费。
如果支付了会费，请返回主代理的总会员数代理商。

我尝试了以下查询，但没有运气：

CREATE TABLE [dbo].[SlipDetails](
    [SlipDetailsID] [int] IDENTITY(1,1) NOT NULL,
    [SlipID] [int] NULL,
    [SlipNumber] [nvarchar](50) NULL,
    [AgentID] [int] NULL,
    [AgentName] [nvarchar](50) NULL,
    [MemberID] [int] NULL,
    [MemberName] [nvarchar](50) NULL,
    [MonthID] [int] NULL,
    [MonthAmount] [int] NULL,
    [LateFine] [int] NULL,
    [SubmittedDateByAgent] [datetime] NULL,
    [ApprovedByAdmin] [nvarchar](1) NULL,
    [ApprovedDate] [datetime] NULL,
    [MonthName] [nvarchar](50) NULL,
    [Blocked] [nvarchar](1) NULL,
 CONSTRAINT [PK_SlipDetails] PRIMARY KEY CLUSTERED 
(
    [SlipDetailsID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]

GO

CREATE TABLE [dbo].[MemberMaster](
    [MemberID] [int] IDENTITY(1,1) NOT NULL,
    [MemberName] [nvarchar](50) NULL,
    [MemberMobile] [varchar](50) NULL,
    [MemberEmail] [nvarchar](50) NULL,
    [MemberDOB] [nvarchar](50) NULL,
    [MemberDOJ] [nvarchar](50) NULL,
    [MemberGender] [nvarchar](50) NULL,
    [MemberGenderID] [int] NULL,
    [MemberAddress] [nvarchar](50) NULL,
    [MemberPhoto] [nvarchar](50) NULL,
    [IsFreeGift] [int] NULL,
    [GiftID] [int] NULL,
    [GiftName] [nvarchar](50) NULL,
    [AgentID] [int] NULL,
    [AgentName] [nvarchar](50) NULL,
    [CardID] [int] NULL,
    [CardNumber] [nvarchar](50) NULL,
    [SID] [int] NULL,
    [SName] [nvarchar](50) NULL,
    [Custom1] [nvarchar](50) NULL,
    [Custom2] [nvarchar](50) NULL,
    [IsActive] [nvarchar](1) NULL,
    [IsBlocked] [nvarchar](1) NULL,
 CONSTRAINT [PK_MemberMaster] PRIMARY KEY CLUSTERED 
(
    [MemberID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]

GO

CREATE TABLE [dbo].[AgentMaster](
    [AgentID] [int] IDENTITY(1,1) NOT NULL,
    [AgentName] [nvarchar](50) NULL,
    [Mobile] [nvarchar](50) NULL,
    [AgentUserName] [nvarchar](50) NULL,
    [AgentPassword] [nvarchar](50) NULL,
    [IsActive] [nvarchar](1) NULL,
    [ParentAgentID] [int] NULL,
    [ParentAgentName] [nvarchar](50) NULL,
    [BankName] [nvarchar](50) NULL,
    [AccountHolderName] [nvarchar](50) NULL,
    [IFSC] [nvarchar](50) NULL,
    [BranchName] [nvarchar](50) NULL,
    [AccountNo] [nvarchar](50) NULL,
    [AgentPhoto] [nvarchar](50) NULL,
    [DOJ] [datetime] NULL,
    [SelectedInDraw] [nvarchar](1) NULL,
 CONSTRAINT [PK_AgentMaster] PRIMARY KEY CLUSTERED 
(
    [AgentID] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]

查询：

SELECT COUNT(dbo.MemberMaster.MemberID) AS CMemberID
FROM dbo.SlipDetails
     INNER JOIN dbo.MemberMaster ON dbo.SlipDetails.MemberID = dbo.MemberMaster.MemberID
WHERE dbo.MemberMaster.AgentID = 203
GROUP BY dbo.MemberMaster.AgentID,
         dbo.SlipDetails.MonthAmount
HAVING(SUM(dbo.SlipDetails.MonthAmount) >= 430);

如何获得每个代理商下的会员的确切计数？任何帮助都会很棒。

Answer 1

Select mm.AgentName,Count(mm.MemberID) as MemberCount from MemberMaster mm
INNER JOIN
(Select AgentID,MemberId from SlipDetails
group by AgentID,MemberID
having Sum(MonthAmount)>=430)sd
on sd.AgentID=mm.AgentID and sd.MemberID=mm.MemberID
Group by mm.AgentID, mm.AgentName

甚至：

Select am.AgentName,MemberCount from AgentMaster am
inner join
(Select mm.AgentID,Count(mm.MemberID) as MemberCount from MemberMaster mm
INNER JOIN
(Select AgentID,MemberId from SlipDetails
group by AgentID,MemberID
having Sum(MonthAmount)>=430)sd
on sd.AgentID=mm.AgentID and sd.MemberID=mm.MemberID
Group by mm.AgentID)mm1
on am.AgentID=mm1.AgentID

Answer 2

试试这个

    WITH SlipDetails_ttl as (
        Select st.MemberID, sum(MonthAmount) as MonthAmount_ttl 
            from SlipDetails as st
        group by st.MemberID
        having sum(MonthAmount)>=430
    )
    Select am.AgentID, count(stt.MemberID) 
    From SlipDetails_ttl as stt 
    join MemberMaster as mm on mm.MemberID = stt.MemberID
    join AgentMaster as am on mm.AgentID = am.AgentID
    group by am.AgentID

Answer 3

尝试一下：

SELECT agt.AgentID, COUNT(*)
FROM dbo.AgentMaster agt -- Get all agents
INNER JOIN dbo.MemberMaster mbr ON agt.AgentID = mbr.AgentID -- Get each agents' members
INNER JOIN dbo.SlipDetails slp ON mbr.MemberID = slp.MemberID -- Get payment details for members
GROUP BY agt.AgentID
HAVING(SUM(slp.MonthAmount)) = 430 -- Only return members that have paid 430

一些假设/注释：

仅查看每个座席的直接成员（不是递归，仅限一个级别）
不考虑3个月的约束，只检查每个成员已支付430

SQL查询计算符合所需条件的人数

3 个答案: