我的问题类似于this MySQL问题，但适用于SQL Server：
是否有函数或查询会返回两个日期之间的天数列表？例如，假设有一个名为ExplodeDates的函数：
SELECT ExplodeDates('2010-01-01', '2010-01-13');
这将返回一个包含值的单个列表：
2010-01-01
2010-01-02
2010-01-03
2010-01-04
2010-01-05
2010-01-06
2010-01-07
2010-01-08
2010-01-09
2010-01-10
2010-01-11
2010-01-12
2010-01-13
我认为日历/数字表可以帮助我。
更新
我决定查看提供的三个代码答案，执行结果 - 占总批次的百分比 - 是：
越低越好
我接受了Rob Farley的答案，因为它是最快的，尽管数字表解决方案（KM和StingyJack在他们的答案中使用）都是我的最爱。 Rob Farley的速度提高了三分之二。
更新2
Alivia的answer更为简洁。我已经改变了接受的答案。
答案 0 :(得分：98)
这几行是sql server中这个问题的简单答案。
WITH mycte AS
(
SELECT CAST('2011-01-01' AS DATETIME) DateValue
UNION ALL
SELECT DateValue + 1
FROM mycte
WHERE DateValue + 1 < '2021-12-31'
)
SELECT DateValue
FROM mycte
OPTION (MAXRECURSION 0)
答案 1 :(得分：66)
尝试这样的事情：
CREATE FUNCTION dbo.ExplodeDates(@startdate datetime, @enddate datetime)
returns table as
return (
with
N0 as (SELECT 1 as n UNION ALL SELECT 1)
,N1 as (SELECT 1 as n FROM N0 t1, N0 t2)
,N2 as (SELECT 1 as n FROM N1 t1, N1 t2)
,N3 as (SELECT 1 as n FROM N2 t1, N2 t2)
,N4 as (SELECT 1 as n FROM N3 t1, N3 t2)
,N5 as (SELECT 1 as n FROM N4 t1, N4 t2)
,N6 as (SELECT 1 as n FROM N5 t1, N5 t2)
,nums as (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) as num FROM N6)
SELECT DATEADD(day,num-1,@startdate) as thedate
FROM nums
WHERE num <= DATEDIFF(day,@startdate,@enddate) + 1
);
然后使用：
SELECT *
FROM dbo.ExplodeDates('20090401','20090531') as d;
编辑（接受后）：
请注意......如果你已经有一个足够大的nums表，那么你应该使用：
CREATE FUNCTION dbo.ExplodeDates(@startdate datetime, @enddate datetime)
returns table as
return (
SELECT DATEADD(day,num-1,@startdate) as thedate
FROM nums
WHERE num <= DATEDIFF(day,@startdate,@enddate) + 1
);
您可以使用以下方式创建这样的表：
CREATE TABLE dbo.nums (num int PRIMARY KEY);
INSERT dbo.nums values (1);
GO
INSERT dbo.nums SELECT num + (SELECT COUNT(*) FROM nums) FROM nums
GO 20
这些行将创建一个包含1M行的数字表...并且比逐个插入它们要快得多。
您不应使用涉及BEGIN和END的函数创建ExplodeDates函数，因为查询优化器根本无法简化查询。
答案 2 :(得分：17)
这完全符合你想要的，修改自Will先前的帖子。不需要辅助表或循环。
WITH date_range (calc_date) AS (
SELECT DATEADD(DAY, DATEDIFF(DAY, 0, '2010-01-13') - DATEDIFF(DAY, '2010-01-01', '2010-01-13'), 0)
UNION ALL SELECT DATEADD(DAY, 1, calc_date)
FROM date_range
WHERE DATEADD(DAY, 1, calc_date) <= '2010-01-13')
SELECT calc_date
FROM date_range;
答案 3 :(得分：3)
我是一个oracle人，但我相信MS SQL Server支持connect by子句：
select sysdate + level
from dual
connect by level <= 10 ;
输出结果为：
SYSDATE+LEVEL
05-SEP-09
06-SEP-09
07-SEP-09
08-SEP-09
09-SEP-09
10-SEP-09
11-SEP-09
12-SEP-09
13-SEP-09
14-SEP-09
Dual只是oracle附带的'虚拟'表（它包含1行，单词'dummy'作为单列的值）。
答案 4 :(得分：2)
DECLARE @MinDate DATETIME = '2012-09-23 00:02:00.000',
@MaxDate DATETIME = '2012-09-25 00:00:00.000';
SELECT TOP (DATEDIFF(DAY, @MinDate, @MaxDate) + 1) Dates = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, @MinDate)
FROM sys.all_objects a CROSS JOIN sys.all_objects b;
答案 5 :(得分：1)
这些日期是否已经存在于数据库中，或者您只想知道两个日期之间的日期？如果是第一个你可以使用 BETWEEN 或＆lt; =＆gt; = 来查找日期之间的日期
示例：
SELECT column_name(s)
FROM table_name
WHERE column_name
BETWEEN value1 AND value2
OR
SELECT column_name(s)
FROM table_name
WHERE column_name
value1 >= column_name
AND column_name =< value2
答案 6 :(得分：1)
您只需更改下面提供的代码中的硬编码值
DECLARE @firstDate datetime
DECLARE @secondDate datetime
DECLARE @totalDays INT
SELECT @firstDate = getDate() - 30
SELECT @secondDate = getDate()
DECLARE @index INT
SELECT @index = 0
SELECT @totalDays = datediff(day, @firstDate, @secondDate)
CREATE TABLE #temp
(
ID INT NOT NULL IDENTITY(1,1)
,CommonDate DATETIME NULL
)
WHILE @index < @totalDays
BEGIN
INSERT INTO #temp (CommonDate) VALUES (DATEADD(Day, @index, @firstDate))
SELECT @index = @index + 1
END
SELECT CONVERT(VARCHAR(10), CommonDate, 102) as [Date Between] FROM #temp
DROP TABLE #temp
答案 7 :(得分：1)
一些想法：
如果你需要列表日期以便循环它们，你可以有一个开始日期和日期计数参数并在创建日期并使用它时进行一个while循环？
使用C＃CLR存储过程并在C＃中编写代码
在代码
中的数据库外执行此操作答案 8 :(得分：0)
绝对是一个数字表，虽然你可能想要使用Mark Redman关于CLR proc / assembly的想法，如果你真的需要这个表现的话。
如何创建日期表（以及创建数字表的超快方法）
/*Gets a list of integers into a temp table (Jeff Moden's idea from SqlServerCentral.com)*/
SELECT TOP 10950 /*30 years of days*/
IDENTITY(INT,1,1) as N
INTO #Numbers
FROM Master.dbo.SysColumns sc1,
Master.dbo.SysColumns sc2
/*Create the dates table*/
CREATE TABLE [TableOfDates](
[fld_date] [datetime] NOT NULL,
CONSTRAINT [PK_TableOfDates] PRIMARY KEY CLUSTERED
(
[fld_date] ASC
)WITH FILLFACTOR = 99 ON [PRIMARY]
) ON [PRIMARY]
/*fill the table with dates*/
DECLARE @daysFromFirstDateInTheTable int
DECLARE @firstDateInTheTable DATETIME
SET @firstDateInTheTable = '01/01/1998'
SET @daysFromFirstDateInTheTable = (SELECT (DATEDIFF(dd, @firstDateInTheTable ,GETDATE()) + 1))
INSERT INTO
TableOfDates
SELECT
DATEADD(dd,nums.n - @daysFromFirstDateInTheTable, CAST(FLOOR(CAST(GETDATE() as FLOAT)) as DateTime)) as FLD_Date
FROM #Numbers nums
现在您有了一个日期表，您可以使用像KM这样的函数（非A PROC）来获取它们的表格。
CREATE FUNCTION dbo.ListDates
(
@StartDate DATETIME
,@EndDate DATETIME
)
RETURNS
@DateList table
(
Date datetime
)
AS
BEGIN
/*add some validation logic of your own to make sure that the inputs are sound.Adjust the rest as needed*/
INSERT INTO
@DateList
SELECT FLD_Date FROM TableOfDates (NOLOCK) WHERE FLD_Date >= @StartDate AND FLD_Date <= @EndDate
RETURN
END
答案 9 :(得分：0)
也许如果你想采取更简单的方式，这应该做到。
WITH date_range (calc_date) AS (
SELECT DATEADD(DAY, DATEDIFF(DAY, 0, CURRENT_TIMESTAMP) - 6, 0)
UNION ALL SELECT DATEADD(DAY, 1, calc_date)
FROM date_range
WHERE DATEADD(DAY, 1, calc_date) < CURRENT_TIMESTAMP)
SELECT calc_date
FROM date_range;
但临时表也是一种非常好的方法。也许您还应该考虑一个填充的日历表。
答案 10 :(得分：0)
在使用我的功能之前，您需要设置一个“帮助程序”表，每个数据库只需执行一次这样的操作：
CREATE TABLE Numbers
(Number int NOT NULL,
CONSTRAINT PK_Numbers PRIMARY KEY CLUSTERED (Number ASC)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
DECLARE @x int
SET @x=0
WHILE @x<8000
BEGIN
SET @x=@x+1
INSERT INTO Numbers VALUES (@x)
END
这是功能：
CREATE FUNCTION dbo.ListDates
(
@StartDate char(10)
,@EndDate char(10)
)
RETURNS
@DateList table
(
Date datetime
)
AS
BEGIN
IF ISDATE(@StartDate)!=1 OR ISDATE(@EndDate)!=1
BEGIN
RETURN
END
INSERT INTO @DateList
(Date)
SELECT
CONVERT(datetime,@StartDate)+n.Number-1
FROM Numbers n
WHERE Number<=DATEDIFF(day,@StartDate,CONVERT(datetime,@EndDate)+1)
RETURN
END --Function
使用它：
select * from dbo.ListDates('2010-01-01', '2010-01-13')
输出：
Date
-----------------------
2010-01-01 00:00:00.000
2010-01-02 00:00:00.000
2010-01-03 00:00:00.000
2010-01-04 00:00:00.000
2010-01-05 00:00:00.000
2010-01-06 00:00:00.000
2010-01-07 00:00:00.000
2010-01-08 00:00:00.000
2010-01-09 00:00:00.000
2010-01-10 00:00:00.000
2010-01-11 00:00:00.000
2010-01-12 00:00:00.000
2010-01-13 00:00:00.000
(13 row(s) affected)
答案 11 :(得分：0)
如果您遇到像我这样禁止程序和功能的情况，并且您的sql用户没有插入权限，因此不允许插入， “设置/声明像@c这样的临时变量是不允许的”，但是你想要生成特定时期的日期列表，比如当前年份做一些聚合，使用这个
select * from
(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) gen_date from
(select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
(select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
(select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
(select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
(select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
where gen_date between '2017-01-01' and '2017-12-31'
答案 12 :(得分：0)
此查询适用于Microsoft SQL Server。
select distinct format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) as aDate
from (
SELECT ones.n + 10 * tens.n + 100 * hundreds.n + 1000 * thousands.n as v
FROM (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) ones(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) tens(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) hundreds(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) thousands(n)
) a
where format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) < cast('2010-01-13' as datetime)
order by aDate asc;
现在让我们来看看它是如何运作的。
内部查询仅返回0到9999之间的整数列表。它将为我们提供10,000个值的范围，用于计算日期。您可以通过添加十分之一和百分之几等行来获得更多日期。
SELECT ones.n + 10 * tens.n + 100 * hundreds.n + 1000 * thousands.n as v
FROM (VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) ones(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) tens(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) hundreds(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) thousands(n)
) a;
此部分将字符串转换为日期，并从内部查询中为其添加数字。
cast('2010-01-01' as datetime) + ( a.v / 10 )
然后我们将结果转换为您想要的格式。这也是列名！
format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' )
接下来，我们只提取不同的值，并为列名提供aDate的别名。
distinct format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) as aDate
我们使用where子句仅过滤您想要的范围内的日期。请注意，我们在此使用列名，因为SQL Server不接受where子句中的列别名aDate。
where format( cast('2010-01-01' as datetime) + ( a.v / 10 ), 'yyyy-MM-dd' ) < cast('2010-01-13' as datetime)
最后，我们对结果进行排序。
order by aDate asc;
答案 13 :(得分：0)
派对迟到了，但我非常喜欢这个解决方案。
CREATE FUNCTION ExplodeDates(@startDate DateTime, @endDate DateTime)
RETURNS table as
return (
SELECT TOP (DATEDIFF(DAY, @startDate, @endDate) + 1)
DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, @startDate) AS DATE
FROM sys.all_objects a
CROSS JOIN sys.all_objects b
)
答案 14 :(得分：0)
Declare @date1 date = '2016-01-01'
,@date2 date = '2016-03-31'
,@date_index date
Declare @calender table (D date)
SET @date_index = @date1
WHILE @date_index<=@date2
BEGIN
INSERT INTO @calender
SELECT @date_index
SET @date_index = dateadd(day,1,@date_index)
IF @date_index>@date2
Break
ELSE
Continue
END
答案 15 :(得分：0)
- ###六分之一的六分之一。假设MsSql的另一种方法
Declare @MonthStart datetime = convert(DateTime,'07/01/2016')
Declare @MonthEnd datetime = convert(DateTime,'07/31/2016')
Declare @DayCount_int Int = 0
Declare @WhileCount_int Int = 0
set @DayCount_int = DATEDIFF(DAY, @MonthStart, @MonthEnd)
select @WhileCount_int
WHILE @WhileCount_int < @DayCount_int + 1
BEGIN
print convert(Varchar(24),DateAdd(day,@WhileCount_int,@MonthStart),101)
SET @WhileCount_int = @WhileCount_int + 1;
END;
答案 16 :(得分：0)
如果您想要打印从特定年份到当前日期的年份。刚改变了接受的答案。
WITH mycte AS
(
SELECT YEAR(CONVERT(DATE, '2006-01-01',102)) DateValue
UNION ALL
SELECT DateValue + 1
FROM mycte
WHERE DateValue + 1 < = YEAR(GETDATE())
)
SELECT DateValue
FROM mycte
OPTION (MAXRECURSION 0)
答案 17 :(得分：-1)
DECLARE @StartDate DATE = '2017-09-13', @EndDate DATE = '2017-09-16'
SELECT date FROM ( SELECT DATE = DATEADD(DAY, rn - 1, @StartDate) FROM (
SELECT TOP (DATEDIFF(DAY, @StartDate, DATEADD(DAY,1,@EndDate)))
rn = ROW_NUMBER() OVER (ORDER BY s1.[object_id])
FROM sys.all_objects AS s1
CROSS JOIN sys.all_objects AS s2
ORDER BY s1.[object_id] ) AS x ) AS y
<强>结果：
2017-09-13
2017-09-14
2017-09-15
2017-09-16
答案 18 :(得分：-1)
这里有答案 How to list all dates between two dates
Create Procedure SelectDates(@fromDate Date, @toDate Date)
AS
BEGIN
SELECT DATEADD(DAY,number,@fromDate) [Date]
FROM master..spt_values
WHERE type = 'P'
AND DATEADD(DAY,number,@fromDate) < @toDate
END
答案 19 :(得分：-1)
SELECT dateadd(dd,DAYS,'2013-09-07 00:00:00') DATES
INTO #TEMP1
FROM
(SELECT TOP 365 colorder - 1 AS DAYS from master..syscolumns
WHERE id = -519536829 order by colorder) a
WHERE datediff(dd,dateadd(dd,DAYS,'2013-09-07 00:00:00'),'2013-09-13 00:00:00' ) >= 0
AND dateadd(dd,DAYS,'2013-09-07 00:00:00') <= '2013-09-13 00:00:00'
SELECT * FROM #TEMP1
答案 20 :(得分：-1)
WITH TEMP (DIA, SIGUIENTE_DIA ) AS
(SELECT
1,
CAST(@FECHAINI AS DATE)
FROM
DUAL
UNION ALL
SELECT
DIA,
DATEADD(DAY, DIA, SIGUIENTE_DIA)
FROM
TEMP
WHERE
DIA < DATEDIFF(DAY, @FECHAINI, @FECHAFIN)
AND DATEADD(DAY, 1, SIGUIENTE_DIA) <= CAST(@FECHAFIN AS DATE)
)
SELECT
SIGUIENTE_DIA AS CALENDARIO
FROM
TEMP
ORDER BY
SIGUIENTE_DIA
详细信息在表DUAL上，但如果您将此表交换为虚拟表，则可以使用。