我正在尝试获取日期,这些日期从开始日期到结束日期每隔5天发生一次。
Eg.
if start date= 11/10/2014 i.e MM/DD/YYYY format
and end date =11/26/2014
then my **expected output** is =
[11/15/2014,11/20/2014,11/25/2014]
我在下面试过但很混淆在哪里运行循环以获得准确的输出。目前,从下面的代码我只在列表中获得1个日期
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.Date;
import java.util.List;
public class TestDate {
// mm/dd/yyyy
public List getDates(Date fromDate,int frequency,Date endDate){
List list=new ArrayList<Date>();
SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
Calendar c = Calendar.getInstance();
c.setTime(fromDate); // Now use today date.
c.add(Calendar.DATE, frequency); // Adding 5 days
String newDate = sdf.format(c.getTime());
String sEndDate=sdf.format(endDate);
if((newDate.compareTo(sEndDate) < 0) || (newDate.compareTo(sEndDate) == 0)){
list.add(newDate);
}
//Weekly=7,Bi-Weekly14,Monthly-30,Semi-Monthly-15
return list;
}
public static void main(String[] args) {
try {
TestDate obj=new TestDate();
SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
Date s = sdf.parse("11/10/2014");
Date e = sdf.parse("11/26/2014");
System.out.println(obj.getDates(s, 5, e));
}
catch(Exception e) {
System.err.println("--exp in main---"+e);
}
}
}
正确答案低于 *Thanks to Almas*
public List getDates(Date fromDate,int frequency,Date e){
List list=new ArrayList<Date>();
Calendar c = Calendar.getInstance();
Calendar c2 = Calendar.getInstance();
c2.setTime(e); // Now use today date.
Date endDate=c2.getTime();
Date newDate=fromDate;
while(true){
c.add(Calendar.DATE, frequency);
newDate=c.getTime();
if(newDate.compareTo(endDate)<=0){
list.add(newDate);
}else{
break;
}
}
//Weekly=7,Bi-Weekly14,Monthly-30,Semi-Monthly-15
return list;
}
答案 0 :(得分:1)
为什么您希望将日期作为字符串并按字典顺序进行比较,而不是将它们作为日期进行比较?
String newDate = sdf.format(c.getTime());
String sEndDate=sdf.format(endDate);
这应该改为
Date newDate = c.getTime();
你也使用两个if条件,你可以在下面这样做:
if (newDate.compareTo(endDate) <= 0) {
list.add(newDate);
}
就循环而言,您应该在getDates方法中执行此操作,如下所示:
Date newDate;
while (true) {
c.add(Calendar.DATE, frequency); // Adding 5 days
newDate = c.getTime();
if (newDate.compareTo(endDate) <= 0) {
list.add(newDate);
} else {
break;
}
}
答案 1 :(得分:0)
利用Apache commons DateUtils。这将使您的代码变得简单
Date tempDate = DateUtils.addDays(fromDate, frequency);
while (tempDate.before(endDate))
{
list.add(tempDate);
tempDate = DateUtils.addDays(tempDate, frequency);
}
return list;
答案 2 :(得分:0)
尝试这个
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.Date;
import java.util.List;
public class NewClass1 {
// mm/dd/yyyy
public List getDates(Date fromDate, int frequency, Date endDate) {
List list = new ArrayList<Date>();
SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
Calendar c = Calendar.getInstance();
c.setTime(fromDate); // Now use today date.
c.add(Calendar.DATE, frequency); // Adding 5 days
String newDate = sdf.format(c.getTime());
//System.out.println("date"+newDate);
String formDate = sdf.format(fromDate);
String sEndDate = sdf.format(endDate);
int x = 1;
while (((newDate.compareTo(sEndDate) > 0) || (newDate.compareTo(sEndDate) != 0)) && x < frequency) {
c.add(Calendar.DATE, frequency);
sEndDate = sdf.format(c.getTime());
x++;
System.out.println("date: " + sEndDate);
list.add(newDate);
}
//Weekly=7,Bi-Weekly14,Monthly-30,Semi-Monthly-15
return list;
}
public static void main(String[] args) {
try {
NewClass1 obj = new NewClass1();
SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
Date s = sdf.parse("11/10/2014");
Date e = sdf.parse("11/26/2014");
obj.getDates(s, 5, e);
} catch (Exception e) {
System.err.println("--exp in main---" + e);
}
}
}
答案 3 :(得分:-2)
在您的代码中,您只需拨打
list.add(...);
一次。
你需要一个(while / for)循环来获得预期的结果。