我有一个必要的程序,使三角螺旋。有谁知道我怎么能改变这个程序,而不是让整条线成为螺旋线,让它由直线段制成?以下是我到目前为止的代码......
void setup(){
int len=100;
int startx =250;
int starty= 250;
float angle = PI;
size (500,500);
spiral_triangle(len, startx,starty,angle);
}
void spiral_triangle(int len, int startx, int starty, float angle){
if (len>1)
{line( startx, starty ,int(startx+len*cos(angle)),int(starty + len*sin(angle)) );
int new_startx = int(startx+len*cos(angle));
int new_starty = int(starty+len*sin(angle));
int new_len = len -10;
float new_angle = angle + PI/1.5;
spiral_triangle(new_len, new_startx,new_starty,new_angle);
}
}
示例...而不是每边一行,我需要这个--------每边......各个线段(有点像虚线或虚线)
答案 0 :(得分:1)
如果我理解正确,你需要一个圆形螺旋而不是一个三角螺旋。以下代码应该实现这一点。
void spiral_triangle(float len, int startx, int starty, float angle){
if (len>1) {
float new_len = len - 0.1;
float new_angle = angle + PI/100;
int oldx = int(startx+len*cos(angle));
int oldy = int(starty+len*sin(angle));
int newx = int(startx+new_len*cos(new_angle));
int newy = int(starty+new_len*sin(new_angle));
line( oldx,oldy,newx,newy);
spiral_triangle(new_len, startx,starty,new_angle);
}
}
答案 1 :(得分:0)
如果您想绘制虚线而不是实线,则必须根据此主题编写自己的代码:
http://processing.org/discourse/beta/num_1202486379.html
奇怪的是,库中没有虚线功能。使用该线程中的一个函数,您可以这样做:
void setup() {
int len=100;
int startx =250;
int starty= 250;
float angle = PI;
size (500, 500);
spiral_triangle(len, startx, starty, angle);
}
void spiral_triangle(int len, int startx, int starty, float angle) {
if (len>1) {
float[] spacing = {2,2};
dashline( startx, starty, int(startx+len*cos(angle)), int(starty + len*sin(angle)), spacing);
int new_startx = int(startx+len*cos(angle));
int new_starty = int(starty+len*sin(angle));
int new_len = len -10;
float new_angle = angle + PI/1.5;
spiral_triangle(new_len, new_startx, new_starty, new_angle);
}
}
/*
* Draw a dashed line with given set of dashes and gap lengths.
* x0 starting x-coordinate of line.
* y0 starting y-coordinate of line.
* x1 ending x-coordinate of line.
* y1 ending y-coordinate of line.
* spacing array giving lengths of dashes and gaps in pixels;
* an array with values {5, 3, 9, 4} will draw a line with a
* 5-pixel dash, 3-pixel gap, 9-pixel dash, and 4-pixel gap.
* if the array has an odd number of entries, the values are
* recycled, so an array of {5, 3, 2} will draw a line with a
* 5-pixel dash, 3-pixel gap, 2-pixel dash, 5-pixel gap,
* 3-pixel dash, and 2-pixel gap, then repeat.
*/
void dashline(float x0, float y0, float x1, float y1, float[ ] spacing)
{
float distance = dist(x0, y0, x1, y1);
float [ ] xSpacing = new float[spacing.length];
float [ ] ySpacing = new float[spacing.length];
float drawn = 0.0; // amount of distance drawn
if (distance > 0)
{
int i;
boolean drawLine = true; // alternate between dashes and gaps
/*
Figure out x and y distances for each of the spacing values
I decided to trade memory for time; I'd rather allocate
a few dozen bytes than have to do a calculation every time
I draw.
*/
for (i = 0; i < spacing.length; i++)
{
xSpacing[i] = lerp(0, (x1 - x0), spacing[i] / distance);
ySpacing[i] = lerp(0, (y1 - y0), spacing[i] / distance);
}
i = 0;
while (drawn < distance)
{
if (drawLine)
{
line(x0, y0, x0 + xSpacing[i], y0 + ySpacing[i]);
}
x0 += xSpacing[i];
y0 += ySpacing[i];
/* Add distance "drawn" by this line or gap */
drawn = drawn + mag(xSpacing[i], ySpacing[i]);
i = (i + 1) % spacing.length; // cycle through array
drawLine = !drawLine; // switch between dash and gap
}
}
}
我希望这会有所帮助。