python3我的函数的递归正确性

时间:2012-11-25 06:11:49

标签: function recursion dictionary python-3.x extraction

我需要帮助解决问题。例如,我有以下字典名为planets

{'Mercury': {'Orbital Radius': '38001200', 'Radius': '243900.7',
'Period': '87.9691'}, 'Ariel': {'Orbital Radius': '8595000', 'Radius':
'60000', 'Period': '2.520379'}, 'Sun': {'Satellites':
'Mercury,Venus,Earth,Mars,Jupiter,Saturn,Uranus,Neptune,Ceres,Pluto,Haumea,Makemake,Eris',
'Orbital Radius': '0', 'Radius': '20890260'}, 'Phobos': {'Orbital
Radius': '3623500.6', 'Radius': '200000', 'Period': '0.31891023'},
'Deimos': {'Orbital Radius': '8346000', 'Radius': '200000.2',
'Period': '1.26244'}, 'Mars': {'Satellites': 'Phobos,Deimos', 'Orbital
Radius': '106669000', 'Radius': '339600.2', 'Period': '686.971'},
'Rhea': {'Orbital Radius': '24000000', 'Radius': '75000', 'Period':
'4.5'}, 'Oberon': {'Orbital Radius': '26235000', 'Radius': '75000',
'Period': '13.463'}, 'Europa': {'Orbital Radius': '36486200',
'Radius': '156000.8', 'Period': '3.551181'}, 'Tethys': {'Orbital
Radius': '13706000', 'Radius': '50000', 'Period': '1.9'}, 'Miranda':
{'Orbital Radius': '5822550', 'Radius': '23500', 'Period': '1.413'},
'Saturn': {'Satellites':
'Mimas,Enceladus,Tethys,Dione,Rhea,Titan,Iapetus', 'Orbital Radius':
'353572956', 'Radius': '6026800', 'Period': '10759.22'}, 'Uranus':
{'Satellites': 'Puck,Miranda,Ariel,Umbriel,Titania,Oberon', 'Orbital
Radius': '453572956', 'Radius': '2555900', 'Period': '30799'},
'Neptune': {'Satellites': 'Triton', 'Orbital Radius': '550000000',
'Radius': '2476400', 'Period': '60190'}, 'Titania': {'Orbital Radius':
'19575000', 'Radius': '75000', 'Period': '8.7058'}, 'Enceladus':
{'Orbital Radius': '10706000', 'Radius': '25000', 'Period': '1.4'},
'Venus': {'Orbital Radius': '57477000', 'Radius': '605100.8',
'Period': '224.698'}, 'Moon': {'Orbital Radius': '18128500', 'Radius':
'173700.10', 'Period': '27.321582'}, 'Triton': {'Orbital Radius':
'40000000', 'Radius': '135300', 'Period': '-5.8'}, 'Ceres': {'Orbital
Radius': '130995855', 'Radius': '48700', 'Period': '1679.67'},
'Mimas': {'Orbital Radius': '8433396', 'Radius': '20600', 'Period':
'0.9'}, 'Titan': {'Orbital Radius': '50706000', 'Radius': '257600',
'Period': '15.945'}, 'Ganymede': {'Orbital Radius': '47160000',
'Radius': '263400', 'Period': '7.15455296'}, 'Umbriel': {'Orbital
Radius': '11983500', 'Radius': '60000', 'Period': '4.144177'},
'Callisto': {'Orbital Radius': '69700000', 'Radius': '241000',
'Period': '16.6890184'}, 'Jupiter': {'Satellites':
'Io,Europa,Ganymede,Callisto', 'Orbital Radius': '210573600',
'Radius': '7149200', 'Period': '4332.59'}, 'Io': {'Orbital Radius':
'22000000', 'Radius': '182100.3', 'Period': '1.7691377186'}, 'Earth':
{'Satellites': 'Moon', 'Orbital Radius': '77098290', 'Radius':
'637100.0', 'Period': '365.256363004'}, 'Dione': {'Orbital Radius':
'17106000', 'Radius': '56000', 'Period': '2.7'}, 'Iapetus': {'Orbital
Radius': '72285891', 'Radius': '75000', 'Period': '79'}}

这是我的太阳能动画代码。我的问题是,我的代码是否会不断检查“卫星”的每个“对象”,如果它们存在则打印出来?它是递归的吗?我整天都在努力工作,检查然后打印!

#code for solar animation
#t = period
#x,y = rootobject coordinates

print("flush false")
scale = 600/max([planets[key]['Orbital Radius'] for key in planets])
t = 0
x = 400
y = 300
print("fillcircle",400,300,planets['Sun']['Radius']*scale)
print("text ", "\"Sun\"",x + planets['Sun']['Radius']*scale,y)


def satellites(planets):
    for 'Satellites' in planets:
        if 'Satellites' not in 'Object':
            return
        else:
            print("refresh")
            print("colour 0 0 0")
            print("clear")
            print("colour 255 255 255")
            r_sat = planets['Object']['Satellites']['Orbital Radius']*scale
            print("circle",x,y,r_sat)
            r_satX = x + math.sin(t*2*math.pi/planets['Object']['Satellites']['Period'])*r_sat
            r_satY = y + math.cos(t*2*math.pi/planets['Object']['Satellites']['Period'])*r_sat
            print("fillcircle",r_satX,r_satY,planets['Object']['Satellites']['Radius']*scale)
            print("text ",['Object']['Satellites'],r_satX + planets['Object']['Satellites']['Radius']*scale,r_satY)
            t += 0.02

system = satellites(planets)
print(system)

我接近我的极限,我已经尝试了我能想到的一切,但我需要帮助!

1 个答案:

答案 0 :(得分:2)

1。我的问题是,我的代码是否不断检查“卫星”的每个“对象”,如果存在则打印出来?

不,你的function satellites()无效的python。这是相当多的错误,但我可以看到你朝着正确的方向前进那种

for 'Satellites' in planets:
    if 'Satellites' not in 'Object':
        return

'Satellites'只是一个字符串,因此for 'string' in 'iterable object'无效python。

if 'Satellites' not in 'Object':与上一行有同样的问题,字符串 'Satellites' 永远不会位于字符串 'Object'

我相信这就是你想要做的事情:

for key in planets.keys():               # For all keys in the outer dic 
    if 'Satellites' not in planets[key]: # Does inner dic have key 'Satellites'
        return

其中key是变量(不是字符串),它将循环中的每个值包含在planets中。因此,第一次key的值为'Mecury'时,key的值第二次为'Sun',依此类推。然后我们查看内部字典{{ 1}}并检查该字典是否具有密钥planets[key]

然后使用'Satellites'而非planets[key]['Satellites']因为密钥planets['Object']['Satellites']从不存在(查看输入文件)。

2。它是递归的吗?

不,你的'Object' function从不打电话给自己,重新阅读我的递归答案:python3 recursion animation in QuickDraw