Question

使用来自另一个问题的代码，我在一个tkinter窗口中嵌入了一个pygame窗口，我试图制作一个在pygame窗口上绘制一个圆圈的tk按钮，一直在试验并避开＆＃39;到目前为止，任何结果都没有。任何想法都会很棒！这是我到目前为止的代码......

import Tkinter as tk
import os
import pygame as py

#         R   G  B
red =   (225, 0, 0)
green = (0, 255, 0)
w, h = 500, 200

p = False

def maketrue(p):
    p = True
    returnp

root = tk.Tk()
window = tk.Frame(root, width=w, height=h)
window.pack()

os.environ['SDL_WINDOWID'] = str(window.winfo_id())

root.update

py.display.init()
screen = py.display.set_mode((w, h))
screen.fill(py.Color(255, 0, 0))
drawbutton = tk.Button(root, text='Draw Circle', command = maketrue(p))
drawbutton.pack()

while True:
    if p == True:
        py.draw.circle(screen, red, (250, 50), 20)
        py.display.update()
    else:
        pass
    py.draw.circle(screen, green, (250, 100), 20)

    root.update()

Answer 1

这意味着做了一段时间，但我现在有时间，这是一些基本代码，程序制作一个tkinter窗口，然后在一个框架中嵌入一个pygame窗口，然后创建另一个框架并按下一个按钮按下该窗口时，调用一个函数告诉pygame在pygame窗口上绘制一个圆圈。

import pygame
import Tkinter as tk
from Tkinter import *
import os


root = tk.Tk()

embed = tk.Frame(root, width = 500, height = 500) #creates embed frame for pygame window
embed.grid(columnspan = (600), rowspan = 500) # Adds grid
embed.pack(side = LEFT) #packs window to the left

buttonwin = tk.Frame(root, width = 75, height = 500)
buttonwin.pack(side = LEFT)

os.environ['SDL_WINDOWID'] = str(embed.winfo_id())
os.environ['SDL_VIDEODRIVER'] = 'windib'

screen = pygame.display.set_mode((500,500))
screen.fill(pygame.Color(255,255,255))

pygame.display.init()
pygame.display.update()


def draw():
    pygame.draw.circle(screen, (0,0,0), (250,250), 125)
    pygame.display.update()


button1 = Button(buttonwin,text = 'Draw',  command=draw)
button1.pack(side=LEFT)

root.update()

while True:
    pygame.display.update()
    root.update()

使用Tkinter在Pygame中画一个圆圈

1 个答案: