Question

写在AKKA文档中

...参与者不应该阻塞（即在占用线程时被动等待）某个外部实体，可能是锁，网络套接字等。阻塞操作应该在一些特殊的线程中完成，该线程发送传递给他们的演员的信息。 来源http://doc.akka.io/docs/akka/2.0/general/actor-systems.html#Actor_Best_Practices

我目前找到了以下信息：

我阅读了Sending outbound HTTP request from Akka / Scala，并在https://github.com/dsciamma/fbgl1
我发现以下文章http://nurkiewicz.blogspot.de/2012/11/non-blocking-io-discovering-akka.html解释了如何将https://github.com/AsyncHttpClient/async-http-client非阻止http客户端与akka一起使用。但是用Scala编写。

我怎样才能编写一个制作非阻塞http请求的actor？

它必须将远程URL页面作为文件，而不是将生成的文件对象发送给主actor。然后master actor将此请求发送给解析器actor以解析文件...

Answer 1

在上一个回复中，Koray对发件人使用了错误的引用，正确的方法是：

public class ReduceActor extends UntypedActor {

@Override
public void onReceive(Object message) throws Exception {
    if (message instanceof URI) {
        URI url = (URI) message;


        AsyncHttpClient asyncHttpClient = new AsyncHttpClient();
        final ActorRef sender = getSender();
        asyncHttpClient.prepareGet(url.toURL().toString()).execute(new AsyncCompletionHandler<Response>() {

            @Override
            public Response onCompleted(Response response) throws Exception {
                File f = new File("e:/tmp/crawler/" + UUID.randomUUID().toString() + ".html");
                // Do something with the Response
                // ...
                // System.out.println(response1.getStatusLine());
                FileOutputStream fao = new FileOutputStream(f);
                IOUtils.copy(response.getResponseBodyAsStream(), fao);
                System.out.println("File downloaded " + f);
                sender.tell(new WordCount(f));
                return response;
            }

            @Override
            public void onThrowable(Throwable t) {
                // Something wrong happened.
            }
        });
    } else
        unhandled(message);
  }

查看akka的另一个帖子：https://stackoverflow.com/a/11899690/575746

Answer 2

我已经以这种方式实现了这一点。

public class ReduceActor extends UntypedActor {
@Override
public void onReceive(Object message) throws Exception {
    if (message instanceof URI) {
        URI url = (URI) message;

        AsyncHttpClient asyncHttpClient = new AsyncHttpClient();

        asyncHttpClient.prepareGet(url.toURL().toString()).execute(new AsyncCompletionHandler<Response>() {

            @Override
            public Response onCompleted(Response response) throws Exception {
                File f = new File("e:/tmp/crawler/" + UUID.randomUUID().toString() + ".html");
                // Do something with the Response
                // ...
                // System.out.println(response1.getStatusLine());
                FileOutputStream fao = new FileOutputStream(f);
                IOUtils.copy(response.getResponseBodyAsStream(), fao);
                System.out.println("File downloaded " + f);
                getSender().tell(new WordCount(f));
                return response;
            }

            @Override
            public void onThrowable(Throwable t) {
                // Something wrong happened.
            }
        });
    } else
        unhandled(message);
}

用于从AKKA发送非阻塞http请求的Java示例

2 个答案: