Question

如何计算用户在指定日期内缺席的总天数？

这是我认为它如何运作的基本思路，但我不能让整个部分发挥作用。

SELECT total(from - until) FROM absences WHERE absences.user_id = 123
AND absence_date_until <= '1999-12-01' AND absence_date_from >=
'2000-12-01'


CREATE TABLE IF NOT EXISTS `absences` (
  `absence_id` int(10) NOT NULL AUTO_INCREMENT,
  `absence_created` datetime DEFAULT NULL,
  `absence_date_from` datetime DEFAULT NULL,
  `absence_date_until` datetime DEFAULT NULL,
  `absence_status` enum('PENDING','APPROVED') NOT NULL,
  `user_id` int(6) NOT NULL,
  PRIMARY KEY (`absence_id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8;

Answer 1

SELECT SUM(datediff(until, from) + 1) total_absences 
FROM   absences 
WHERE  absences.user_id = 123
       AND absence_date_until <= '1999-12-01' 
       AND absence_date_from  >= '2000-12-01'

Answer 2

在mysql中选择datediff（）

SELECT datediff(absence_date_from- absence_date_until) 
FROM absences WHERE absences.user_id = 123
AND absence_date_until <= '1999-12-01' 
AND absence_date_from >=  '2000-12-01'

mysql计算缺席的总天数

2 个答案: