Question

我正在尝试编写sql，我可以在每个DATE使用groupBy返回每天的金额。

我的字段是金额和transaction_date，我的sql是：

select id,    
Amount as amount,    
transactionDate as transaction_date      
from transaction    
WHERE transactionDate IN (SELECT DISTINCT TOP 7 transactionDate from transaction
order by transactionDate)

因此，我的sql语法错误，无法弄清楚下一步该怎么做。

Answer 1

使用汇总和分组依据

select transactionDate     
sum(Amount) as amount,    
from transaction  
where transactionDate>=cast(now()-INTERVAL -7 DAY as date) and transactionDate<cast(now() as date)
group by transactionDate

Answer 2

尝试以下方式

select date(transactionDate) as transaction_date  
sum(Amount) as amount           
from transaction    
WHERE date(transactionDate)>=  DATE_ADD(current_date(),INTERVAL -7 DAY)
group by date(transactionDate)

BTW Top是非mysql的sql服务器关键字

Answer 3

谢谢大家，给我一条可以走的路。我找到了解决方案。非常感谢。

 SELECT
 DATE(transaction_date) AS TransactionDate, SUM(amount) AS Amount
 FROM transaction
 WHERE type = 'spend'
 AND transaction_date>=  DATE_ADD(NOW(), INTERVAL -7 DAY)
 GROUP BY TransactionDate

SQL-计算最近7天的金额

3 个答案: