Question

我有这个表，我在一周指定假期。我想使用这些字段计算2个特定日期之间的总工作日。

CREATE TABLE [tbl_Shift](
[OffDay1] [nvarchar](25) NOT NULL CONSTRAINT [DF_tbl_Shift_OffDay1]  DEFAULT (N'Sunday'),
[IsAlternateOffDay2] [bit] NULL,
[OffDay2] [nvarchar](25) NULL
)

INSERT INTO [tbl_Shift] VALUES ('Sunday', 'True', 'Saturday')

我写了这个查询，但我无法得到正确的日子。它应该给出23天，因为每周有2个假期，总共31天，但我得到26天。

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate = '2018/05/01'
SET @EndDate = '2018/05/31'


SELECT
   (DATEDIFF(dd, @StartDate, @EndDate+1)) -(DATEDIFF(wk, @StartDate, @EndDate))
   -(CASE WHEN IsAlternateOffday2 = 1 THEN 1 END) FROM HRM.tbl_Shift

Answer 1

每个周末减去2天。如果星期日是一周的第一天或最后一天，请检查您的服务器配置。这可以在周末之前解决问题。

SELECT DATEPART(WEEKDAY,'20180506') --Checks if Sunday is Day 1 or Day 7

DECLARE @start DATETIME = '20180501'
DECLARE @end DATETIME = '20180531'

SELECT DATEDIFF(DAY,@start,@end+1) - (DATEDIFF(WEEK,@start,@end+1)*2)

更新：

使用COALESCE将NULLS替换为替代值。

DECLARE @offdate DATETIME = NULL

SELECT COALESCE(@offdate,GETDATE())

Answer 2

这将给出23：

SELECT
    (DATEDIFF(dd, @StartDate, @EndDate+1)) -(DATEDIFF(wk, @StartDate, @EndDate))
    -ISNULL((CASE WHEN IsAlternateOffday2 = 1 THEN (DATEDIFF(wk, @StartDate, @EndDate)) END), 0) 
FROM HRM.tbl_Shift

Answer 3

试试这个

DECLARE @StartDate DATE ='2018-05-01',
        @EndDate DATE ='2018-05-31'
;WITH CTE
AS
(
SELECT DATEADD(DD,Number-1,@StartDate) MOnthDates,
       DATENAME(DW,DATEADD(DD,Number-1,@StartDate)) As DayNAmes,
       CASE WHEN DATENAME(DW,DATEADD(DD,Number-1,@StartDate)) IN ('Saturday','Sunday') THEN 0 ELSE 1 END WeekDays
FROM master.dbo.spt_values
WHERE [Type]='P'
AND Number Between 1 AND 10000
)
SELECT COUNT(WeekDays)  AS WeekDaysCount
FROM CTE
WHERE WeekDays<>0
AND MOnthDates Between @StartDate AND DATEADD(DAY,1,@EndDate)

结果

WeekDaysCount
-------------
23

演示：http://rextester.com/TOLYT35075

计算一个月的总工作日数

3 个答案: