我编写了一个Worker类和Worker的驱动程序类。 我的工人阶级正在编译并显示所需的输出.. 但是在数组和StringTokenizer中，我面临的主要问题是... TestWorker.java 的 32 有错误，我不知道为什么会给出 问题是......
（i）声明一个数组，该数组可以存储使用数据（name，workerID和hourlyRate）构造的最多5个 Worker 对象的引用。
（ii）现在允许用户重复输入workerID和小时，直到用户输入空字符串。读取这些值并在相应的对象上调用方法 addWeekly（）（通过搜索数组以找到具有指定ID的对象）。如果输入了不存在的ID，则显示相应的错误消息。
（iii）计算并显示所有工人的工资
请参阅下面的代码.....
// Worker.java
public class Worker {
public final double bonus=100;
protected String name, workerID;
protected double hourlyRate, totalHoursWorked,tax,grossSalary,netSalary;
public Worker(){
}
public Worker(String name, String workerID, double hourlyRate){
this.name = name;
this.workerID = workerID;
this.hourlyRate = hourlyRate;
}
public void addWeekly(double hoursWorked){
this.totalHoursWorked = this.totalHoursWorked + hoursWorked;
}
public double gross(){
grossSalary = (totalHoursWorked*hourlyRate);
if(totalHoursWorked>=150){
grossSalary = grossSalary +100;
}
return grossSalary;
}
public double netAndTax(){
netSalary = grossSalary;
if(grossSalary>500){
tax = (grossSalary - 500) *0.3;
netSalary = (grossSalary - tax);
}
return netSalary;
}
public String getName(){
return this.name;
}
public String getWorkerID(){
return this.workerID;
}
public double getHourlyRate(){
return this.hourlyRate;
}
public double getTotalHours(){
return totalHoursWorked;
}
public double getGrossSalary(){
return grossSalary;
}
public void addToGross(double amt){
grossSalary = grossSalary + amt;
}
public void displaySalary(){
System.out.print("Name: " +getName() + "\nID :" + getWorkerID()
+ "\nHourly Rate: " + getHourlyRate()+ "\nTotalHours Worked" + getTotalHours() +
"\nGross pay" + getGrossSalary() + "\nTax: " + netAndTax() +
"\nNet Pay: " + netAndTax());
}
}
// TestWorker.java
import java.util.Scanner;
import java.util.StringTokenizer;
public class TestWorker {
public static void main(String args[]){
Worker e = new Worker("John Major","s123",15.0);
e.addWeekly(45);
e.addWeekly(40);
e.addWeekly(32);
e.addWeekly(38);
e.gross();
e.netAndTax();
e.displaySalary();
Worker[] worklist = new Worker[5];
worklist[0] = new Worker("Richard Cooper","s1235",20.0);
worklist[1] = new Worker("John Major","s1236",18.0);
worklist[2] = new Worker("Mary Thatcher","s1237",15.0);
worklist[3] = new Worker("David Benjamin","s1238",16.0);
worklist[4] = new Worker("Jack Soo","s1239",25.0);
Scanner input = new Scanner(System.in);
String name;
double hourly;
do{
System.out.println("\n");
System.out.print("Please Enter ID and hours-worked in a given week: ");
name = input.nextLine();
StringTokenizer string = new StringTokenizer(name,"+");
String[] array =new String[(string.countTokens)];
for(int i=0;i<=4;i++){
if(array[0].equals(worklist[0])){
e.getName();
e.getWorkerID();
e.addWeekly(Double.parseDouble(array[0]));
e.gross();
e.displaySalary();
}
else if(array[0].equals(worklist[1])){
e.getName();
e.getWorkerID();
e.addWeekly(Double.parseDouble(array[1]));
e.gross();
e.displaySalary();
}
else if(array[0].equals(worklist[2])){
e.getName();
e.getWorkerID();
e.addWeekly(Double.parseDouble(array[2]));
e.gross();
e.displaySalary();
}
else if(array[0].equals(worklist[3])){
e.getName();
e.getWorkerID();
e.addWeekly(Double.parseDouble(array[3]));
e.gross();
e.displaySalary();
}
else if(array[0].equals(worklist[4])){
e.getName();
e.getWorkerID();
e.getHourlyRate();
e.addWeekly(Double.parseDouble(array[4]));
e.gross();
e.displaySalary();
}
else{
System.out.println("Please Enter correct information");
}
}
System.out.println();
while(string.hasMoreElements()){
System.out.println(string.nextElement());
}
}
while(name.isEmpty()==false);
}
}
答案 0 :(得分：1)
首先，您已将countTokens指定为字段，因为它实际上是此行上的方法：
String[] array = new String[(string.countTokens)]; // Incorrect
String[] array = new String[(string.countTokens())]; // Correct
现在您似乎在+标志上分割输入？所以你预期的输入是s123+12的意思，这意味着ID s123 worked 12 hours this week。所以为了解决类似你可能需要一个看起来像这样的循环：
Scanner input = new Scanner(System.in);
System.out.println("\n");
System.out.print("Please Enter ID and hours-worked in a given week: ");
String enteredString = input.nextLine();
while (!enteredString.isEmpty()) {
StringTokenizer stringtok = new StringTokenizer(enteredString, "+");
String id = stringtok.nextToken();
Double hours = Double.parseDouble(stringtok.nextToken());
for (int i = 0; i < 5; i++) {
if (worklist[i].getWorkerID().equals(id)) {
worklist[i].addWeekly(hours);
break;
}
}
System.out.println("\n");
System.out.print("Please Enter ID and hours-worked in a given week: ");
enteredString = input.nextLine();
}
for (int i = 0; i < 5; i++) {
worklist[i].gross();
worklist[i].netAndTax();
worklist[i].displaySalary();
}
请记住，这是非常粗糙的，我并不完全清楚你的指示，你究竟想要达到的目标。
答案 1 :(得分：0)
为什么不考虑将为您提供字符串数组的String.split() name.split("\\+")