Question

我有一个已经标记过的文件但是我需要将每个标记存储在一个数组中以便以后用作参数。我该怎么做呢？

//         Read in File           //
FILE *fp;
char buffer[100];

fp = fopen(params, "r");

printf("Here is filename...");
printf("%s\n", params);

fseek(fp, 0, SEEK_END);
//byte_size = ftell(fp);
rewind(fp);

if (fgets(buffer,sizeof(buffer),fp) != NULL)
{
    char*p, *b;
    b = buffer;
    printf("parsing %s", buffer);
    while ((p = strsep(&b, ",")) != NULL)
    {
        printf("param: %s\n",p);
    }
}
fclose(fp);

Answer 1

使用链接列表并稍后将其转换为数组可能会很好，因为我们不知道有多少令牌。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char *strsep(char **stringp, const char *delim);

typedef struct node_tag {
    char *str;
    struct node_tag* next;
} list_node;

list_node* create_node(const char *str) {
    list_node* n = malloc(sizeof(list_node));
    if (n == NULL) exit(1);
    if (str == NULL) {
        n->str = NULL;
    } else {
        n->str = malloc(sizeof(char) * (strlen(str) + 1));
        if (n->str == NULL) exit(1);
        strcpy(n->str, str);
    }
    n->next = NULL;
    return n;
}

int main(void) {
    const char *params = "dummy";
    FILE *fp;
    char buffer[100];
    list_node *head = NULL;
    list_node **tail = &head;
    unsigned int count = 0;
    unsigned int i;
    char **array;
    fp = stdin;//fopen(params, "r");
    printf("Here is filename...");
    printf("%s\n", params);
    fseek(fp, 0, SEEK_END);
    //byte_size = ftell(fp);
    rewind(fp);

    if (fgets(buffer,sizeof(buffer),fp) != NULL)
    {
        char*p, *b;
        b = buffer;
        printf("parsing %s", buffer);
        while ((p = strsep(&b, ",")) != NULL)
        {
            printf("param: %s\n",p);
            *tail = create_node(p);
            tail = &(*tail)->next;
            count++;
        }


    }

    array = malloc(sizeof(char*) * count);
    if (array == NULL) return 1;
    for (i = 0; i < count && head != NULL; i++) {
        list_node *next = head->next;
        array[i] = head->str;
        // Don't free(head->str) because it is used
        free(head);
        head = next;
    }

    for (i = 0; i < count; i++) {
        printf("array[%u] = %s\n", i, array[i]);
    }
    for (i = 0; i < count; i++) free(array[i]);
    free(array);

    //fclose(fp);
    return 0;
}

Answer 2

如果你知道令牌的数量，你可以简单地使用数组。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char *strsep(char **stringp, const char *delim);

#define ARRAY_SIZE 8

int main(void) {
    const char *params = "dummy";
    FILE *fp;
    char buffer[100];
    char *array[ARRAY_SIZE];
    int array_count = 0;
    int i;
    fp = stdin;//fopen(params, "r");
    printf("Here is filename...");
    printf("%s\n", params);
    fseek(fp, 0, SEEK_END);
    //byte_size = ftell(fp);
    rewind(fp);

    if (fgets(buffer,sizeof(buffer),fp) != NULL)
    {
        char*p, *b;
        b = buffer;
        printf("parsing %s", buffer);
        while ((p = strsep(&b, ",")) != NULL)
        {
            printf("param: %s\n",p);
            if (array_count < ARRAY_SIZE)
            {
                array[array_count] = malloc(sizeof(char) * (strlen(p) + 1));
                strcpy(array[array_count], p);
                array_count++;
            }
        }


    }

    for (i = 0; i < array_count; i++) {
        printf("array[%u] = %s\n", i, array[i]);
    }
    for (i = 0; i < array_count; i++) free(array[i]);

    //fclose(fp);
    return 0;
}

将令牌存储到数组中以便稍后作为参数传递

2 个答案: