我完成了整个程序,它运行正常。但是,我遇到了StringTokenizer的问题。我有一个名为Worker.java的类和一个名为TestWorker.java的测试类......
在测试课程中,我计算并打印出总工作时间,总薪水等。 但是我被困在1位,即我必须在数组中存储名称,ID和小时费率,然后使用StringTokenizer,我必须提示用户输入工作人员ID和小时费率。
当用户输入用户工作者姓名和ID时,程序输出将向用户显示工人的每小时费率......
或换句话说......
允许用户重复输入worker-ID和Hours,直到用户输入并清空字符串。读取值并在相应的对象上调用addWeekly()方法(通过搜索数组来查找具有指定ID的对象)。如果输入了不存在的ID,则显示相应的错误消息。
请参阅下面的编码并根据您的需要进行修改....
//Worker.java
public class Worker {
public final double bonus=100;
protected String name;
protected String workerID;
protected double hourlyRate;
protected double hoursWorked;
protected double weekHour;
protected double tax;
protected double grossSalary;
protected double netSalary;
public Worker() {
}
public Worker(String name,String workerID,double hourlyRate){
this.name = name;
this.workerID = workerID;
this.hourlyRate = hourlyRate;
}
public void addWeekly(double weekHour){
hoursWorked = hoursWorked + weekHour;
}
public double gross()
{
grossSalary = (hoursWorked*hourlyRate);
if(hoursWorked>=150)
{
grossSalary = grossSalary +100;
}
return grossSalary;
}
public double taxAndNet()
{
tax = (grossSalary - 500) * 0.3;
netSalary = (grossSalary-tax);
return netSalary;
}
public String getName()
{
return name;
}
public String getWorkerID()
{
return workerID;
}
public double getHourly()
{
return hourlyRate;
}
public double getTotalHours()
{
return hoursWorked;
}
public double getGrossSalary()
{
return grossSalary;
}
public void addToGross(double amt)
{
grossSalary = grossSalary + amt;
}
public void displaySalary()
{
System.out.println("Name :" + name + "\nID :" + workerID +"\nHourly rate : "+ hourlyRate +"\nTotal Hours Worked " + hoursWorked +"\nGross Pay: "+getGrossSalary()+ "\nTax : "+tax +"\nNetpay :" +netSalary);
}
}
//TestWorker.java
import java.util.StringTokenizer;
import java.util.Scanner;
public class TestWorker {
public static void main(String args[]) {
Worker e = new Worker("John Major","s123",15.0);
e.addWeekly(45);
e.addWeekly(40);
e.addWeekly(32);
e.addWeekly(38);
e.gross();
e.taxAndNet();
e.displaySalary();
Worker[] worklist = new Worker[5];
worklist[0] = new Worker("Richard Cooper","s1235",20.0);
worklist[1] = new Worker("John Major","s1236",18.0);
worklist[2] = new Worker("Mary Thatcher","s1237",15.0);
worklist[3] = new Worker("David Benjamin","s1238",16.0);
worklist[4] = new Worker("Jack Soo","s1239",25.0);
Scanner input = new Scanner(System.in);
String name;
do{
System.out.print("Please enter your name and worker ID: ");
name = input.nextLine();
StringTokenizer string = new StringTokenizer(name,"+");
System.out.println("******|||||*******");
while(string.hasMoreElements()){
System.out.println(string.nextElement());
}
}
while(name.isEmpty()==false);
String s = "Five+Three=Nine-One";
String arr[];
//declare it with 3 tokens as seen above:
StringTokenizer st = new StringTokenizer(s, "+=-");
//the array size is the number of tokens in the String:
arr = new String[st.countTokens()];
//when there are still more tokens, place it in the array:
int i = 0;
while(st.hasMoreTokens()){
arr[i] = st.nextToken();
i++;
}
//determine the word with the largest length:
int indexMax = 0;
for( i = 1; i < arr.length; i++){
if(arr[i].length() > arr[indexMax].length())
indexMax = i;
}
System.out.println("The largest element is in index: "
+ indexMax);
} //main
} //class
答案 0 :(得分:0)
请告诉我们您的java版本。从jdk 1.4.2开始,你应该使用String.split(...)而不是旧的Stringtokenizer。查看本教程TIP: A little tutorial about String.split();