StringTokenizer和Array Java

时间:2012-10-08 15:20:09

标签: java arrays stringtokenizer

我完成了整个程序,它运行正常。但是,我遇到了StringTokenizer的问题。我有一个名为Worker.java的类和一个名为TestWorker.java的测试类......

在测试课程中,我计算并打印出总工作时间,总薪水等。 但是我被困在1位,即我必须在数组中存储名称,ID和小时费率,然后使用StringTokenizer,我必须提示用户输入工作人员ID和小时费率。

当用户输入用户工作者姓名和ID时,程序输出将向用户显示工人的每小时费率......

或换句话说......

允许用户重复输入worker-ID和Hours,直到用户输入并清空字符串。读取值并在相应的对象上调用addWeekly()方法(通过搜索数组来查找具有指定ID的对象)。如果输入了不存在的ID,则显示相应的错误消息。

请参阅下面的编码并根据您的需要进行修改....

//Worker.java

public class Worker {
    public final double bonus=100;
    protected String name;
    protected String workerID;
    protected double hourlyRate;
    protected double hoursWorked;
    protected double weekHour;
    protected double tax;
    protected double grossSalary;
    protected double netSalary;


    public Worker() {
    }

    public Worker(String name,String workerID,double hourlyRate){
        this.name = name;
        this.workerID = workerID;
        this.hourlyRate = hourlyRate;
    }

    public void addWeekly(double weekHour){

        hoursWorked = hoursWorked + weekHour;

    }

    public double gross()
    {
        grossSalary = (hoursWorked*hourlyRate);
        if(hoursWorked>=150)
        {
            grossSalary = grossSalary +100;
        }
        return  grossSalary;
    }

    public double taxAndNet()
    {
        tax = (grossSalary - 500) * 0.3;
        netSalary = (grossSalary-tax);
        return netSalary;
    }

    public String getName()
    {
        return name;
    }

    public String getWorkerID()
    {
        return workerID;
    }

    public double getHourly()
    {
        return hourlyRate;
    }

    public double getTotalHours()
    {
        return hoursWorked;
    }

    public double getGrossSalary()
    {
        return grossSalary;
    }

    public void addToGross(double amt)
    {
        grossSalary = grossSalary + amt;
    }

    public void displaySalary()
    {

        System.out.println("Name :" + name + "\nID :" + workerID +"\nHourly rate : "+ hourlyRate +"\nTotal Hours Worked " + hoursWorked +"\nGross Pay: "+getGrossSalary()+ "\nTax : "+tax +"\nNetpay :" +netSalary);
    }

}


//TestWorker.java

import java.util.StringTokenizer;
import java.util.Scanner;

public class TestWorker {

    public static void main(String args[]) {

        Worker e = new Worker("John Major","s123",15.0);
        e.addWeekly(45);
        e.addWeekly(40);
        e.addWeekly(32);
        e.addWeekly(38);
        e.gross();
        e.taxAndNet();
        e.displaySalary();

        Worker[] worklist = new Worker[5];

        worklist[0] = new Worker("Richard Cooper","s1235",20.0);
        worklist[1] = new Worker("John Major","s1236",18.0);
        worklist[2] = new Worker("Mary Thatcher","s1237",15.0);
        worklist[3] = new Worker("David Benjamin","s1238",16.0);
        worklist[4] = new Worker("Jack Soo","s1239",25.0);

        Scanner input = new Scanner(System.in);
        String name;

        do{
            System.out.print("Please enter your name and worker ID: ");
            name = input.nextLine();

            StringTokenizer string = new StringTokenizer(name,"+");
            System.out.println("******|||||*******");
            while(string.hasMoreElements()){
                System.out.println(string.nextElement());
            }
        }
        while(name.isEmpty()==false);

         String s = "Five+Three=Nine-One";
        String arr[];

          //declare it with 3 tokens as seen above:
      StringTokenizer st = new StringTokenizer(s, "+=-");

      //the array size is the number of tokens in the String:
      arr = new String[st.countTokens()];

          //when there are still more tokens, place it in the array:
      int i = 0;
          while(st.hasMoreTokens()){
        arr[i] = st.nextToken();
                i++;
          }

      //determine the word with the largest length:
          int indexMax = 0;
          for( i = 1; i < arr.length; i++){
             if(arr[i].length() > arr[indexMax].length())
            indexMax = i;
          }

      System.out.println("The largest element is in index: "
                + indexMax);

  } //main
} //class

1 个答案:

答案 0 :(得分:0)

请告诉我们您的java版本。从jdk 1.4.2开始,你应该使用String.split(...)而不是旧的Stringtokenizer。查看本教程TIP: A little tutorial about String.split();