这是一个基于查找最大嵌套间隔集大小的问题。
有许多区间,每个区间由包含起点和终点(si,ei)的对定义。如果i2完全位于i1内,则两个间隔i1和i2称为嵌套。示例: - (2,6)和(3,4)是嵌套的,因为(3,4)是(2,6)的一部分。类似地,k个区间i1,i2,i3 ...... ik被称为嵌套,如果,i2位于i1内,i3位于i2内,......等等。根据给定的间隔确定最大间隔集的大小,以便该集合中的所有间隔都可以生成嵌套。
我按照以下方式思考: - 让我们采取例如 - (0,7)(0,5)(1,21)(1,9)(2,8)(2,4)(3, 20)(4,16)(5,15)(6,21)按照a [i-1]< = a [i]&& b [i-1]> = b [i]从第一个区间开始我们开始一个链表..如果下一个区间进入一个区间,我们向下移动节点并遍历在节点下创建的图形(除了主list)..我们将最大级别节点的指针存储在此图中新间隔可以适合的位置..并在链表中进一步遍历以查看当前间隔来自谁...最后我们有一个指向节点的指针我们必须附加当前间隔..并将此节点的级别与我们已有的最大级别进行比较.....最大级别的最终值是设置的最大嵌套间隔的大小。
上述解决方案的复杂性很可能是: - O(n(k + l)+ nlogn)
我想这很难得到它,但我没有其他选择...如果有人有任何其他算法来解决它...请发布因为我的算法需要更长的时间来实现(很多数据结构)参与)...谢谢!!!
答案 0 :(得分:0)
编辑:问题的一些解决方案已发布here,其中包括两个声称为O(n lg n)的解决方案。但是,我不认为O(n lg n)解决方案有效。我在该页面上发表评论,说明原因。如果有人有O(n lg n)解决方案,我很乐意听到。
二次解决方案
使用动态编程可以在O(n ^ 2)时间内解决此问题:
MaxNestedIntervals
来解决问题*注: 步骤1可以使用此处的解决方案在O(n lg n)时间内完成:Sub O(n^2) algorithm for counting nested intervals? 可以使用任何基于比较的最佳排序算法在O(n lg n)时间内完成步骤2。 可能有一种方法可以优化第3步,但我还没有找到它。
<强>复发强>
MaxNestedIntervals(i) =
max {j = 0 to i-1} :
1 + MaxNestedIntervals(j) if interval i contains interval j
0 if interval i doesn't contain interval j
基本情况
MaxNestedIntervals(i) =
0 if interval i contains 0 intervals
1 if interval i contains 1 interval
示例代码
import java.util.*;
public class MaxNestedIntervals {
public static void main(String[] args) {
Interval[] intervals = new Interval[10];
intervals[0] = new Interval(0, 7);
intervals[1] = new Interval(0, 5);
intervals[2] = new Interval(1, 21);
intervals[3] = new Interval(1, 9);
intervals[4] = new Interval(2, 8);
intervals[5] = new Interval(2, 4);
intervals[6] = new Interval(3, 20);
intervals[7] = new Interval(4,16);
intervals[8] = new Interval(5,15);
intervals[9] = new Interval(6,21);
int n = intervals.length;
AugmentedInterval[] augmentedIntervals = new AugmentedInterval[n];
for (int i = 0; i < n; i++) {
augmentedIntervals[i] = new AugmentedInterval(intervals[i]);
}
for (int i = 0; i < n; i++) {
AugmentedInterval outerInterval = augmentedIntervals[i];
for (int j = 0; j < n; j++) {
if (i == j) {
continue;
}
AugmentedInterval innerInterval = augmentedIntervals[j];
if (outerInterval.contains(innerInterval)) {
outerInterval.numContainedIntervals++;
if (outerInterval.childInterval == null) {
outerInterval.childInterval = innerInterval;
}
}
}
}
Arrays.sort(augmentedIntervals, new Comparator<AugmentedInterval>() {
public int compare(AugmentedInterval i, AugmentedInterval j) {
return i.numContainedIntervals - j.numContainedIntervals;
}
});
int maxNestedIntervals = 0;
AugmentedInterval parentInterval = null;
for (int i = 0; i < n; i++) {
AugmentedInterval currentInterval = augmentedIntervals[i];
if (currentInterval.numContainedIntervals == 0) {
currentInterval.maxNestedIntervals = 0;
} else if (currentInterval.numContainedIntervals == 1) {
currentInterval.maxNestedIntervals = 1;
} else {
int maxNestedIntervalsForCurrentInterval = 0;
for (int j = 0; j < i; j++) {
AugmentedInterval candidateNestedInterval = augmentedIntervals[j];
int maxNestedIntervalsForCurrentCandidate = candidateNestedInterval.maxNestedIntervals + 1;
if (currentInterval.contains(candidateNestedInterval) && maxNestedIntervalsForCurrentCandidate >= maxNestedIntervalsForCurrentInterval) {
maxNestedIntervalsForCurrentInterval = maxNestedIntervalsForCurrentCandidate;
currentInterval.childInterval = candidateNestedInterval;
}
}
currentInterval.maxNestedIntervals = maxNestedIntervalsForCurrentInterval;
if (maxNestedIntervalsForCurrentInterval >= maxNestedIntervals) {
maxNestedIntervals = maxNestedIntervalsForCurrentInterval;
parentInterval = currentInterval;
}
}
}
if (n == 0) {
System.out.println("The largest set of nested intervals is the empty set.");
} else if (maxNestedIntervals == 0) {
System.out.println("The largest set of nested intervals has 1 interval.\n");
System.out.println("That interval is:");
} else {
System.out.println("The largest set of nested intervals has " + (maxNestedIntervals + 1) + " intervals.\n");
System.out.println("Those intervals are:");
}
for (AugmentedInterval currentInterval = parentInterval; currentInterval != null; currentInterval = currentInterval.childInterval) {
System.out.println(currentInterval);
}
System.out.println();
}
private static class Interval implements Comparable<Interval> {
public int start = 0;
public int end = 0;
public Interval(int start, int end) {
this.start = start;
this.end = end;
}
public int size() {
return this.end - this.start;
}
public boolean contains(Interval other) {
return (this.start <= other.start && this.end >= other.end);
}
public int compareTo(Interval other) {
return this.size() - other.size();
}
public String toString() {
return "[" + this.start + ", " + this.end + "]";
}
}
private static class AugmentedInterval extends Interval {
public int numContainedIntervals = 0;
public int maxNestedIntervals = 0;
public AugmentedInterval childInterval = null;
public AugmentedInterval(Interval interval) {
super(interval.start, interval.end);
}
}
}