发布和解析从Android到PHP的数据

时间:2012-10-07 04:52:39

标签: php android sql-server java-ee

我在我的android程序中收集了一些不同数据到不同数据类型的三个不同变量。

现在我需要将这些数据发布到服务器中,我应该能够解析这些数据并将它们存储在我的本地数据库中。我正在使用php进行服务器端脚本编写。

有人可以举例说明如何使用httppost进行此操作吗?

2 个答案:

答案 0 :(得分:2)

在Android方面,您不应该network operations in the main UI Thread

Android Side:

public class SendPOSTRequest extends AsyncTask<List<BasicNameValuePair>, Void, String>
{
    private DefaultHttpClient _httpClient;
    private String _url = "";

    public SendPOSTRequest(String url){
        _url = url;
        _httpClient = new DefaultHttpClient();
    }

    @Override
    protected String doInBackground(List<BasicNameValuePair>... postParameters) {
        String responseString = "";

        try
        {
            HttpPost postRequest = new HttpPost(_url);
            postRequest.setEntity(new UrlEncodedFormEntity(postParameters[0]));

            HttpResponse response = _httpClient.execute(postRequest);
            StatusLine statusLine = response.getStatusLine();

            // check if post was successfull
            if (statusLine.getStatusCode() == HttpStatus.SC_OK) {
                ByteArrayOutputStream out = new ByteArrayOutputStream();

                HttpEntity entity = response.getEntity();
                entity.writeTo(out);
                out.close();
                responseString = out.toString();

                if (entity != null) {
                    entity.consumeContent();
                }
            }
        }
        catch(Exception ex)
        {
            ex.getMessage();
        }

        return responseString;
    }
}

在您的活动中,您可以使用“SendPostRequest”类,如下所示:     SendPOSTRequest webPOSTRequest = new SendPOSTRequest(yourWebURLWithYourPHPFunction);     list postParams = new ArrayList();     postParams.add(new BasicNameValuePair(“Name”,“viperbone”));     String result = webGetRequestUsersEntries.execute(postParams).get();

在服务器端,我使用php-script和PDO(PHP数据对象),因为it helpts to protect from sql injection

Serverside PHP-Script:

try
{
    $DBH = new PDO("mysql:host=yourWebURL;dbname=yourDBName", username, password);

    # substr(str,pos,len) - Make sure POST-Data aren't too long (255 chars max) because my database-field is 255 chars
    $NameClear = substr($_POST['Name'], 0, 255);

    # named placeholders 
    $STH = $DBH->prepare("INSERT INTO `yourTableName` (Name) VALUES ( :name )");
    $STH->bindParam(':name', $NameClear);

    # setting the fetch mode
    $STH->setFetchMode(PDO::FETCH_ASSOC);
    $STH->execute(); 

    # I return 1 for a successful insertion 
    echo "1";

    $DBH = null;
}  
catch(PDOException $e) {
} 

我希望它有所帮助...

答案 1 :(得分:2)

向服务器发送请求并获取响应json是实现的最佳方式。

以下是向服务器发送httppost json请求并处理json响应的好例子。

http://www.codeproject.com/Articles/267023/Send-and-receive-json-between-android-and-php