Question

我正在使用这个论坛很长一段时间，首先，我想说感谢帮助我很多次。这是我第一次找不到答案，这让我感到非常震惊......

我正在尝试编写一个超级简单的应用程序，它可以从/向数据库获取/发布数据。问题是，我无法发布数据（得到的很好）。我正在使用一个php文件，它应该从Android设备获取数据，并将其发送到数据库。首先，我不能将它发布到我的php文件中。我已经尝试了所有（我知道）。

PHP文件 -

$test=$_POST['v']; print $_POST['v'];

Java文件 -

public void postData（）抛出ClientProtocolException，IOException {

    // Create a new HttpClient and Post Header
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost post = new HttpPost("https://www.myweb.coom/test.php");

    try {
        // Add your data
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
        nameValuePairs.add(new BasicNameValuePair("v", "123"));
        post.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        // Execute HTTP Post Request
        httpclient.execute(post);

    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
    } catch (IOException e) {
        // TODO Auto-generated catch block
    }
}

当我把Log。*它告诉我，everthing是好的。看来PHP没有得到任何数据......

编辑ASYNTASK ----- public class Upload extends AsyncTask {

@Override
protected String doInBackground(String... params) {
    try {
        JSONObject json = new JSONObject();
        json.put("UserName", "test2");
        json.put("FullName", "1234567");
        HttpParams httpParams = new BasicHttpParams();
        HttpConnectionParams.setConnectionTimeout(httpParams,
                10000);
        HttpConnectionParams.setSoTimeout(httpParams, 10000);
        HttpClient client = new DefaultHttpClient(httpParams);
        //

        String url = "http://my WAMP server/test.php"+ 
                            "json={\"UserName\":1,\"FullName\":2}";

        HttpPost request = new HttpPost(url);
        request.setEntity(new ByteArrayEntity(json.toString().getBytes(
                "UTF8")));
        request.setHeader("json", json.toString());
        HttpResponse response = client.execute(request);
        HttpEntity entity = response.getEntity();
        // If the response does not enclose an entity, there is no need
        if (entity != null) {
            InputStream instream = entity.getContent();

            String result = "gr8 Success";
            Log.i("Read from server", result);

        }
    } catch (Throwable t) {
        Log.e("Request failed: " ,"ERR"+ t.toString());
    }

}

}

MainActivity -

public void postData(View v) { //starts on button click

    if(upload!=null){
        if(upload.getStatus()!= AsyncTask.Status.FINISHED){
            Log.d("postData","no need to start AsyncTask");
            return;
        }

    }
    upload= new Upload();
    upload.execute();
    Log.i("Async", "Starting...");

}

PHP- $ json = $ _ GET ['json']; $ obj = json_decode（$ json）;

               $posts = array(1);
               header('Content-type: application/json');
                 echo json_encode(array('posts'=>$posts));

Answer 1

您的网址包含2＆＃39; o。你应该写https://www.myweb.com/test.php，而不是https://www.myweb.coom/test.php

Answer 2

您使用的是哪个版本的Android SDK。如果您使用的是4.1及更高版本的SDK，请检查您是否在辅助线程而不是UI线程上进行http调用。由于您没有报告异常，因此您已获得Internet权限。

将数据从android发布到PHP

2 个答案: