Question

我正在使用Oracle SQL Developer。我基本上有一个包含列的图片表：

[DATE_CREATED（日期），NUM_of_PICTURES（int）]

如果我选择*，我会得到类似于的输出：

01-May-12    12
02-May-12    15
03-May-12    09
...
...
01-Jun-12    20
...
etc.

我试图将这些图片总和合并为每月数字而不是每日数。

我尝试过这样的事情：

select Month(DATE_CREATED), sum(Num_of_Pictures))
from pictures_table
group by Month(DATE_CREATED);

这会输出错误：

ORA-00904: "MONTH": invalid identifier
00904. 00000 -  "%s: invalid identifier"
*Cause:    
*Action:
Error at Line: 5 Column: 9

我是否有月份功能错误？

Answer 1

我倾向于在输出中包含年份。一种方式：

select to_char(DATE_CREATED, 'YYYY-MM'), sum(Num_of_Pictures)
from pictures_table
group by to_char(DATE_CREATED, 'YYYY-MM')
order by 1

另一种方式（更标准的SQL）：

select extract(year from date_created) as yr, extract(month from date_created) as mon,
       sum(Num_of_Pictures)
from pictures_table
group by extract(year from date_created), extract(month from date_created)
order by yr, mon;

请记住订单，因为您可能想要按顺序排序，并且无法保证在分组后返回行的顺序。

Answer 2

对于Oracle：

select EXTRACT(month from DATE_CREATED), sum(Num_of_Pictures)
from pictures_table
group by EXTRACT(month from DATE_CREATED);

Answer 3

我正在MSSQL中这样做

获取每月数据：

  @app.route('/upload', methods=['GET', 'POST'])
  def index():
    form = MyForm()
    if request.method == 'POST':   
      if form.validate_on_submit():
        blah blah blah I do something......
        return redirect(url_for('index'))

  return render_template('upload.html', form=form)

使用PIVOT获取每月数据：

 SELECT YEAR(DATE_CREATED) [Year], MONTH(DATE_CREATED) [Month], 
     DATENAME(MONTH,DATE_CREATED) [Month Name], SUM(Num_of_Pictures) [Pictures Count]
    FROM pictures_table
    GROUP BY YEAR(DATE_CREATED), MONTH(DATE_CREATED), 
     DATENAME(MONTH, DATE_CREATED)
    ORDER BY 1,2

Answer 4

对于MS SQL，您可以这样做。

    select  CAST(DATEPART(MONTH, DateTyme) as VARCHAR) +'/'+ 
CAST(DATEPART(YEAR, DateTyme) as VARCHAR) as 'Date' from #temp
    group by Name, CAST(DATEPART(MONTH, DateTyme) as VARCHAR) +'/'+
 CAST(DATEPART(YEAR, DateTyme) as VARCHAR)

Answer 5

您可以使用：

    select FK_Items,Sum(PoiQuantity) Quantity  from PurchaseOrderItems POI
    left join PurchaseOrder PO ON po.ID_PurchaseOrder=poi.FK_PurchaseOrder
    group by FK_Items,DATEPART(MONTH, TransDate)

如何在一年中查询GROUP BY月份

5 个答案: