Question

现在我想做一个应用程序来测试静止不动的人或钛的运动。我使用加速度计和3轴x，y，z的操作加速度。我必须用公式测试那个问题..！< / p>

Answer 1

首先，通过公式accel = sqrt(accel_x^2 + accel_y^2 + accel_z^2)获得与移动方向无关的标量加速度，其中^2表示 2的幂，sqrt表示平方根。之后，应用一些低通滤波器来消除随机噪声。 Here是一个很好的算法，使用alpha=0.8是一个很好的方法。现在，您可以看到滤波加速度是否大于某个阈值（灵敏度取决于此阈值）。祝你好运！

Answer 2

另一种选择是使用GPS。

var win = Ti.UI.createWindow({ backgroundColor: 'white' });

// WARNING: This will only work well outside, where the phone can get a good GPS signal.
var label = Ti.UI.createLabel({ text: 'Traveled 0 ft' });
win.add(label);

// Set up the geolocation code
Ti.Geolocation.accuracy = Ti.Geolocation.ACCURACY_BEST;
Ti.Geolocation.distanceFilter = 0.1;
Ti.Geolocation.purpose = 'To track how far you have traveled!';
var lastLocation = null, totalFtTraveled = 0;

/**
 * This function is called by the phone every time we have new geolocation data. It writes out where the user currently is.
 * @param e An argument given to us by the phone with information such as accuracy, latitude, and longitude.
 */
function reportPosition(e) {
    if (!e.success || e.error) {
        label.text = 'error: ' + JSON.stringify(e.error);
    }
    else {
        if (lastLocation != null) {
            var lat1 = lastLocation.latitude, lon1 = lastLocation.longitude;
            var lat2 = e.coords.latitude, lon2 = e.coords.longitude;
            var kmTraveled = 3963.0 * Math.acos(
                Math.sin(lat1 / 57.2958) * Math.sin(lat2 / 57.2958)
                    + Math.cos(lat1 / 57.2958) * Math.cos(lat2 / 57.2958)
                    * Math.cos(lon2 / 57.2958 - lon1 / 57.2958)
            );
            var ftTraveled = kmTraveled * 3280.8399;
            totalFtTraveled += ftTraveled;
            label.text = 'Traveled ' + totalFtTraveled + 'ft';
        }
        lastLocation = e.coords;
    }
}

// This will get the location right now, and will get the phone ready to listen for the user's current location.
Ti.Geolocation.getCurrentPosition(reportPosition);
// And this fires whenever the "distance filter" is surpassed -- with a filter of 1, this happens every 1 meter or so.
Ti.Geolocation.addEventListener('location', reportPosition);

var reset = Ti.UI.createButton({ title: 'Reset', bottom: 10, height: 50, width: 200 });
reset.addEventListener('click', function() {
    totalFtTraveled = 0;
    label.text = 'Traveled 0ft';
});
win.add(reset);

win.open();

测试人站立不动或钛的运动

2 个答案: