Question

$query = mysql_query(SELECT * FROM test WHERE SUBSTRING(date,0,4)="1392") //for example 1392
echo query['name'];

我想得到4个第一个字符，并检查它与1392是否相等。但它返回1054我的列名类型是varchar，我不知道这个。

Answer 1

MySQL从1开始计算char，而不是从0开始计算php。尝试

SUBSTRING(date,1,4)="1392"

或者如果你想要年份

YEAR(date)="1392"

http://dev.mysql.com/doc/refman/5.5/en/string-functions.html#function_substring

编辑测试示例

CREATE TABLE babak (name VARCHAR(20) NOT NULL, date VARCHAR(10) NOT NULL);
INSERT INTO babak SELECT 'test', '1391/11/11';
INSERT INTO babak SELECT 'correct', '1932/11/11';

SELECT * FROM babak WHERE YEAR(date) = 1932;
+---------+------------+
| name    | date       |
+---------+------------+
| correct | 1932/11/11 |
+---------+------------+

SELECT * FROM babak WHERE SUBSTRING(date, 1, 4) = 1932;
+---------+------------+
| name    | date       |
+---------+------------+
| correct | 1932/11/11 |
+---------+------------+

Answer 2

因此，您的日期位于varchar，格式为yyyy/MM/dd，请尝试以下方式：

SELECT   *
  FROM   test 
 WHERE   SUBSTRING(`date`,1,4) = '1932'

<强> CLICK HERE FOR DEMO

Answer 3

mysql_query只返回一个资源，你需要使用该资源来获取结果

$resource = mysql_query('SELECT * FROM test WHERE SUBSTRING(date,1,4)="1392"')
$result = mysql_fetch_assoc($resource);
echo $result['name'];

Substring返回一个数字值而不是varchar

3 个答案: