Question

可能重复：
PHP take all combinations

我正在考虑用PHP制作一些能够显示所有车牌组合的东西。例如：

您有3个盒子可以填写最多2个值

喜欢

BOX1 BOX2 BOX3
75   PM   M5 
7S   PH   MS
Z5   PN   H5
ZS   RM   HS
25   RH   N5
2S   RN   NS

NOT BOX1+BOX1+BOX1
It needs to show me
ex. 75-PM-M5
ex. 75-PH-MS
ex. 75-PN-MS
ex. 75-PM-H5
ex. 75-PH-H5
ex. 75-PN-H5
So, BOX1+BOX2+BOX3

The PHP script needs to calculate all the combinations for BOX1+BOX2+BOX3
So BOX1 value1 and value2 are ONE value not two separate values. 
In BOX2 value1 and value2 are also ONE value not two separate values and so on.

If I want all combinations of 
BOX1'91' + BOX2'HF' + BOX3'PF'
BOX1'74' + BOX2'RT' + BOX3'YT'

It will calculate an amount of 2x2x2=8 combinations 

ex. 91-HF-PF
ex. 91-HF-YT
ex. 91-RT-PF
ex. 91-RT-YT
ex. 74-HF-PF
ex. 74-HF-YT
ex. 74-RT-PF
ex. 74-RT-YT

示例pincode

您需要输入4个密码来使用您的apm卡

PIN1+PIN2+PIN3+PIN4
1    1    1    1
2    2    2    2
3    3    3    3
4    4    4    4
5    5    5    5
6    6    6    6
7    7    7    7
8    8    8    8
9    9    9    9
0    0    0    0

所以你总共有10x10x10x10 = 10.000组合，它必须显示所有组合

如果有人能帮助我，我会感激不尽

Answer 1

代码：

<?php

function combinations($arr, $n)
{
    $res = array();

    foreach ($arr[$n] as $item)
    {
        if ($n==count($arr)-1)
            $res[]=$item;
        else
        {
            $combs = combinations($arr,$n+1);

            foreach ($combs as $comb)
            {
                $res[] = "$item $comb";
            }
        }
    }
    return $res;
}

// Your ARRAY (first array is like 'BOX1', etc - )
// you can put as many items in each 'BOX' as you like... 
// and as many 'boxes' as you like
$words = array(array('A','B'),array('C','D'), array('E','F'));

$combos = combinations($words,0);  // ALWAYS, call it with 0 as the last parameter
print_r($combos);

?>

输出

Array
(
    [0] => A C E
    [1] => A C F
    [2] => A D E
    [3] => A D F
    [4] => B C E
    [5] => B C F
    [6] => B D E
    [7] => B D F
)

我认为这完全是你需要的......： - ）

PHP可能的组合3个2个值的数组

1 个答案: