我创建了一个使用乌龟图形绘制不同形状的程序。底部有一个离散的网格,5x5,位于400px到400px的JFrame之上。它包裹着顶部/底部和左/右,以防形状结束。
我现在需要做的是添加一个2d数组,创建一个400x400的0s数组。如果乌龟移动通过任何像素(对应于2d阵列中的一个点),则需要将0更改为1.什么是最好的方法?我们最终正在努力实现康威生命游戏的功能。
答案 0 :(得分:0)
在我看来,最好的方法是跟踪龟的位置(X& Y),用double
变量指示方向,然后用基本三角法计算下一个'像素'那个tutrtle击中了。我假设您将使用计时器或循环运行此代码,因此它看起来像这样:
//This code is somehwere in your program
class Turtle
{
private double x;
private double y;
private double direction; //direction in radians
public double getX() {
return x;
}
public void setX(double x) {
this.x = x;
}
public double getY() {
return y;
}
public void setY(double y) {
this.y = y;
}
public double getDirection() {
return direction;
}
public void setDirection(double direction) {
while(direction > Math.PI * 2)
{
direction -= Math.PI * 2;
}
while(direction < 0)
{
direction += Math.PI * 2;
}
this.direction = direction;
}
}
private static final int GRID_WIDTH = 400;
private static final int GRID_HEIGHT = 400;
private Turtle myTurtle = new Turtle();
private boolean[][] grid = new boolean[GRID_WIDTH][GRID_HEIGHT];
JFrame myJFrame = new JFrame();
private Graphics gridImage = myJFrame.getGraphics();
private void initialise()
{
for(int y = 0; y < GRID_HEIGHT; y++)
{
for(int x = 0; x < GRID_WIDTH; x++)
{
grid[x][y] = false;
}
}
gridImage.setColor(Color.BLACK);
gridImage.fillRect(0, 0, GRID_WIDTH, GRID_HEIGHT);
gridImage.setColor(Color.white);
}
//This code would be inside the loop or timer callback function
private void myMainFunction()
{
double newX, newY;
double deltaX, deltaY;
deltaX = Math.cos(myTurtle.getDirection());
deltaY = Math.sin(myTurtle.getDirection());
newX = myTurtle.getX() + deltaX;
newY = myTurtle.getY() + deltaY;
if(newX < 0)
{
newX += GRID_WIDTH;
}
else if(newX > GRID_WIDTH)
{
newX -= GRID_WIDTH;
}
if(newY < 0)
{
newY += GRID_HEIGHT;
}
else if(newY > GRID_HEIGHT)
{
newY -= GRID_HEIGHT;
}
grid[(int)Math.floor(newX)][(int)Math.floor(newY)] = true;
gridImage.fillRect((int)Math.floor(newX), (int)Math.floor(newY), 1, 1);
myJFrame.update(gridImage);
myTurtle.setX(newX);
myTurtle.setY(newY);
}