Question

我正在创建一个跟踪数据库，收集信息以报告小时，每日，每周，每月，每年，每个级别，每个级别和每层。因此，我有一个名为tracker的表，它由一个表的子集组成，反映了不同的报告（即table["ThisHour"]等）。我想知道是否有办法巩固所有这些只是添加相同信息的线路。这是我正在使用的功能，以及两个子表（而不是我上面列出的8个）：

function exp_update(xp, gold, str, con, dex, wis, int, luck, bpracs, btrains, pracs, trains, qp)
local xtable = tracker[playername]["Exp"]
addto(xtable["ThisHour"],"Exp",xp)
addto(xtable["ThisHour"],"Gold",gold)
addto(xtable["ThisHour"],"BonusStr",str)
addto(xtable["ThisHour"],"BonusCon",con)
addto(xtable["ThisHour"],"BonusDex",dex)
addto(xtable["ThisHour"],"BonusWis",wis)
addto(xtable["ThisHour"],"BonusInt",int)
addto(xtable["ThisHour"],"BonusLuck",luck)
addto(xtable["ThisHour"],"BonusPracs",bpracs)
addto(xtable["ThisHour"],"BonusTrains",btrains)
addto(xtable["ThisHour"],"Pracs",pracs)
addto(xtable["ThisHour"],"Trains",trains)
addto(xtable["ThisHour"],"Qp",qp)
addto(xtable["ThisHour"],"Quests")
addto(xtable["ThisLevel"],"Exp",xp)
addto(xtable["ThisLevel"],"Gold",gold)
addto(xtable["ThisLevel"],"BonusStr",str)
addto(xtable["ThisLevel"],"BonusCon",con)
addto(xtable["ThisLevel"],"BonusDex",dex)
addto(xtable["ThisLevel"],"BonusWis",wis)
addto(xtable["ThisLevel"],"BonusInt",int)
addto(xtable["ThisLevel"],"BonusLuck",luck)
addto(xtable["ThisLevel"],"BonusPracs",bpracs)
addto(xtable["ThisLevel"],"BonusTrains",btrains)
addto(xtable["ThisLevel"],"Pracs",pracs)
addto(xtable["ThisLevel"],"Trains",trains)
addto(xtable["ThisLevel"],"Qp",qp)
addto(xtable["ThisLevel"],"Quests")
end

正如您所看到的，仅仅两个子表已经有很多行。这是每个子表的14行代码，或者，如果我把它们全部放进去，那么我希望尽可能少地整合112行代码。

addto函数是定义的，如果你需要它：

function addto(t,k,v)
t[k] = t[k] + (v or 1)
end

Answer 1

我要说这样做：

local function exp_update_actual(vars)
  local blocks = {"ThisHour", "ThisLevel"} --Add others as needed.
  local xtable = tracker[playername]["Exp"]

  for i, block in ipairs(blocks) do
    for key, value in pairs(vars) do
      addto(xtable[block], key, value)
    end
  end
end

function exp_update(xp, gold, str, con, dex, wis, int, luck, bpracs, btrains, pracs, trains, qp)
  local vars =
  {
    Exp = xp or false,  --nil keys won't exist. false ones will.
    Gold = gold or false,
    BonusStr = str or false,
    BonusCon = con or false,
    BonusDex = dex or false,
    BonusWis = wis or false,
    BonusInt = int or false,
    BonusLuck = luck or false,
    BonusPracs = bpracs or false,
    BonusTrains = btrains or false,
    Pracs = pracs or false,
    Trains = trains or false,
    Qp = qp or false,
    Quests = false,
  }
  exp_update_actual(vars);
end

Lua：将相同的信息添加到多个子表中 - 更简单的方法？

1 个答案: