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假设我有类似下面的数据,我想用matplotlib
在3D图形/曲面中绘图。我该怎么做?
按照@JouniK.Seppänen的回答,我认为我需要meshgrid()
,但我认为我的轴数据不是很正确。如果我有数据(在JSON中),如:
{
"data": {
"Random": [
[1834, 3353, 4602, 5471, 6522, 7873],
[2637, 8575, 8357, 10329, 9742, 10359],
[3648, 10602, 10667, 10751, 10666, 10552],
[4570, 10220, 9202, 10460, 10329, 10928],
[5879, 10788, 10832, 10923, 11075, 10989],
[6783, 11104, 10235, 10499, 11024, 10731],
[7074, 11097, 10222, 10613, 10508, 10767],
[7300, 11002, 10727, 11073, 10328, 10864]],
"LRU": [
[123, 155, 201, 223, 296, 321],
[143, 590, 1046, 1566, 1924, 2434],
[163, 1167, 1774, 2578, 3363, 3980],
[182, 1172, 2259, 3038, 4200, 4907],
[219, 1718, 3044, 3658, 5236, 5680],
[709, 2263, 3588, 4551, 5262, 6197],
[2065, 3865, 4430, 5024, 5986, 6617],
[3048, 4249, 5029, 5790, 6157, 6826]],
"FIFO": [
[180, 269, 350, 424, 580, 601],
[230, 906, 1446, 2009, 2408, 2902],
[316, 1590, 2261, 3042, 3848, 4457],
[473, 1664, 2781, 3542, 4764, 5398],
[665, 2290, 3609, 4194, 5781, 6207],
[1158, 2826, 4115, 5064, 5751, 6613],
[2457, 4375, 4974, 5471, 6464, 7077],
[3512, 4724, 5485, 6272, 6684, 7312]]
},
"workingSetAxis": [2, 22, 42, 62, 82, 102, 122, 142],
"stabilityAxis": [0.0, 0.2, 0.4, 0.6, 0.8, 1.0]
}
其中workingSetAxis
应该是x轴,stabilityAxis
是y轴。我做了类似
plot(jsonObj["data"]["FIFO"], jsonObj["workingSetAxis"], jsonObj["stabilityAxis"])
def plot(data, workingSetAxis, stabilityAxis):
# make axis data
X, Y = numpy.meshgrid(workingSetAxis, stabilityAxis)
Z = data
fig = plt.figure()
ax = fig.add_subplot(111, projection="3d")
ax.plot_wireframe(X, Y, Z)
plt.show()
并得到类似的东西:
与我从excel获得的图表(对于FIFO数据)非常不同
我相信我的轴数据或其他东西是错误的,但是哪个?
答案 0 :(得分:6)
尝试绘制数据的转置,例如,使用
def plot(data, workingSetAxis, stabilityAxis):
# make axis data
X, Y = numpy.meshgrid(workingSetAxis, stabilityAxis)
Z = numpy.transpose(data) #<--- This is the only line I have changed.
fig = plt.figure()
ax = fig.add_subplot(111, projection="3d")
ax.plot_wireframe(X, Y, Z)
plt.show()
您的示例数据给出了以下图表:
答案 1 :(得分:4)
参见例如this example。使用meshgrid将X和Y值转换为2D数组,然后将数据值用作Z。