SQL语法 - 有子句吗?

时间:2012-03-28 13:44:19

标签: sql having-clause

我应该知道这一点 - 但我不知道,任何人都可以用语法帮助我。

假设我正在跟踪越野接力赛中的跑步者,我有一个主要的联赛表,将跑步者与比赛联系起来......还有跑步者表,告诉我他们何时/何时开始他们的腿以及在哪里/当他们结束时...还有沿路线记录的检查点。

要求每个跑步者都有一个起点和终点 - 但是,这并不总是正确输入* - 我需要一个查询来拉出在比赛中没有两种类型的参赛者的跑步者。

(*是的我正在修复数据输入方面的事情)

THX

结构:

RACE TABLE 
 raceID (int)
 runnerID (int)

STOPS TABLE
 runnerID (int)
 stopTypeID (int)  -- fk to stop type
 when (timestamp)
 sequence (smallint)

我还没有“拥有”任何东西 - 因为我被我需要的东西所吸引......

获得跑步者和比赛日志的基本问题是

SELECT *
FROM RACES R
JOIN STOPS S ON S.runnerID = R.runnerID
WHERE R.RaceID = 133



RESULTS
1 = start 
2 = check point
3 = rest point
4 = end

RACEID  RUNNERID    STOPTYPEID
133     21      1 
133     21      4
133     21      3
133     21      2
133     21      2
133     21      2
133     21      2
133     21      2
133     23      2
133     23      2
133     23      2
133     23      2
133     23      4

注意跑步者23缺少类型'1'(开始) 我想要一个缺少数据的比赛中的跑步者名单...如果我说1和4是必需的....

(感谢抱歉不发布所需的'数据')

3 个答案:

答案 0 :(得分:1)

对你的结构略有猜测,但是:

SELECT RR.RunnerId
FROM Race AS R
INNER JOIN RaceRunners AS RR
  ON <whatever>
LEFT OUTER JOIN Runners AS Starters
  On Starters.ID = RR.RunnersID
  AND Starters.Type = 'StartPoint' -- don't know how you're specifying this.
LEFT OUTER JOIN Runners AS Finishers
  On Finishers.ID = RR.RunnersID
  AND Finishers.Type = 'EndPoint' -- don't know how you're specifying this.
WHERE Starters.<Whatever> IS NULL
OR Finishers.<Whatever> IS NULL

答案 1 :(得分:0)

您可以通过这种方式获得两种停止类型(开始,结束)中每个人的停留次数,这也会为您提供一个列,显示跑步者是否有开始或结束登记。

create table #race
(
    raceid int,
    runnerid int
)
create table #stops
(
    runnerid int,
    stoptypeid int,
)

insert into #race values(133, 21)
insert into #race values(133, 23)
insert into #race values(133, 20)
insert into #race values(133, 33)

insert into #stops values(21, 1)
insert into #stops values(21, 4)
insert into #stops values(21, 3)
insert into #stops values(21, 2)
insert into #stops values(21, 2)
insert into #stops values(21, 2)
insert into #stops values(21, 2)
insert into #stops values(21, 2)
insert into #stops values(23, 2)
insert into #stops values(23, 2)
insert into #stops values(23, 2)
insert into #stops values(23, 2)
insert into #stops values(23, 4)

insert into #stops values(20, 3)
insert into #stops values(20, 1)

insert into #stops values(33, 4)
insert into #stops values(33, 1)


    SELECT r.raceid
        , r.runnerid
        , (select COUNT(*) 
            FROM #stops s
            WHERE S.runnerID = R.runnerID
                AND s.stoptypeid IN (1, 4)) as StartEndStops
    , CASE WHEN (SELECT COUNT(*) FROM #stops s WHERE S.runnerID = R.runnerID AND s.stoptypeid = 1) = 1 
            THEN 'Start Check-in'
            ELSE ''
        END as 'Start'
    , CASE WHEN (SELECT COUNT(*) FROM #stops s WHERE S.runnerID = R.runnerID AND s.stoptypeid = 4) = 1
            THEN 'End Check-in'
            ELSE ''
        END as 'End'
    FROM #race R    

drop table #race
drop table #stops

结果:

RaceId    RunnerId  StartEndStops     Start             End
133       21         2            Start Check-in    End Check-in
133       23         1                              End Check-in
133       20         1            Start Check-in
133       33         2            Start Check-in    End Check-in

答案 2 :(得分:0)

我最终使用了这个 - 虽然我仍然很好奇它是否是最佳解决方案...... 我仍然将'详细'等同于'低效' - 而且我不确定这是一个好心态。 我只是想知道它是否混乱,代码比必须更优雅地说明SQL引擎会“更喜欢”......

当然 - 这是抽象的 - 在Q中运行了很多过滤 - 为了简化'概念',我把它切成了一个简单的分钟 - 谢谢

SELECT DISTINCT RaceID, RunnerID 
FROM (
  SELECT 
     raceID
    ,runnerID
    ,(
    SELECT count(stops.ID)
      FROM races
      JOIN stops
     WHERE raceid = main.raceID
       AND STOPTYPEID = 1
) AS poStart
,(
    SELECT count(stops.ID)
      FROM races
      JOIN stops
     WHERE raceid = main.raceID
       AND STOPTYPEID = 4
) AS poEnd


FROM races

WHERE x BETWEEN '2012-03-01 00:00:00.0' AND '2012-03-31 23:59:59.9'

ORDER BY race
) AS T1 WHERE poStart = 0 OR poEnd = 0