有条款......？

Question

！[在此处输入图像说明] [1]我正在处理数据库并对有条款进行了一些查询。

我有一张桌子

sales 
(
  id number(5) primary key,
  amt number(10),
  house_no varchar2 (10),
  city varchar2 (10)
)

我的问题是，我想找到每个条目中city和house_no相同的特定sales_id及其计数。

我试图解决它但尚未达到目的。我正在使用oracle 10g。

Answer 1

SQLFiddle

SELECT count(*), s2.house_no, s2.city FROM sales s1
  INNER JOIN sales s2 ON s1.id = s2.id 
  GROUP BY s2.city, s2.house_no
  HAVING count(*) > 1;

将输出显示为

| COUNT(*) | HOUSE_NO |   CITY |
|----------|----------|--------|
|        2 |      102 |   Pune |
|        3 |      540 | Sangli |

Reference用于多列的GROUP BY子句

Answer 2

试试这个：

select id, cnt
  from (select city, house_no, count(*) as cnt
          from sales t
         group by city, house_no) t,
       sales c
 where t.city = c.city
   and t.house_no = c.house_no

Prathamesh 07 ： 你好我的问题的进一步描述是....

<强>解决方案：

select count(*) as cnt, city, house_no
          from sales t
         group by city, house_no
having count(*)>1