Question

我有一个非常简单的逻辑如下：

var divert:Number = 0;
for (var connection in _connections) {
    trace("target: " + _connections[connection].target + " || i: " + (i + 1));
    if(int(_connections[connection].target) != (i + 1)) {
        trace("bad connection");
        divert++;
    }
}

问题是当i + 1和int(_connections[connection].target)相等时，if语句返回true，如下面trace()语句的输出中所示：

target: 0 || i: 1
bad connection
target: 1 || i: 1
bad connection

任何人都可以看到导致这种情况发生的原因吗？

编辑：根据请求包含的功能：

public function loadListener(i:Number, onProgress:Function, onComplete:Function):Void
    {
        trace("load listening to: "+i);
        trace("next in queue: " + _queues["lower"][0] + " | " + _queues["upper"][0]);
        _functions[i] = {onProgress:onProgress, onComplete:onComplete};
        if (_queues["lower"][0] != i + 1 || _queues["upper"][0] != i + 1) {
            var divert:Number = 0;
            for (var connection in _connections) {
                trace("target: "+_connections[connection].target+" || i: "+(i+1));
                if(int(_connections[connection].target) != (i + 1)) {
                    trace("bad connection");
                    divert++;
                }
            }
            if (divert == _connections.length) {
                _diversion = i + 1;
                trace("divert: "+divert+" || connections: "+_connections.length);
            }
        }
    }

Answer 1

首先，为什么在使用

时使用for(var)循环

var divert:Number = 0;
for each(var connection in _connections) {
    trace("target: " + connection.target + " || i: " + (i + 1));
    if(int(connection.target) != (i + 1)) {
        trace("bad connection");
        divert++;
    }
}

要进一步调试，请替换

trace("target: " + connection.target + " || i: " + (i + 1));

带

trace("target: " + int(connection.target) + " || i: " + (i + 1));

如果此描述为零，则表示问题出在哪里。

您可以尝试

if(connection.target.toString() != (i + 1).toString()) {

AS：if语句评估错误

1 个答案: