Question

我希望以下列格式创建一个列表：

2012 (2) 
- January (1) 
- March (1) 
2011 (1) 
- March (1)

来自以下格式的日期数组：

Array
(
    [0] => Array
        (
            [year] => 2012
            [month] => 3
        )

    [1] => Array
        (
            [year] => 2012
            [month] => 1
        )

    [2] => Array
        (
            [year] => 2011
            [month] => 3
        )

)

此列表由以下查询提供，我也建议如何返回数据。这对我来说是最合乎逻辑的一步。

SELECT YEAR(post_date) as `year`, MONTH(post_date) as `month` FROM posts ORDER BY post_date DESC

我在这里死路一条。我不知道我是不是看到了一些显而易见的事情，或者我是否认为这太复杂了但我无法弄清楚从哪里开始。

Answer 1

假设您可能有多个具有相同月/年的行：

# first sort into a 2-level array of post counts
$by_year = array();
$year_counts = array();
foreach ($rows as $row){
    $by_year[$row['year']][$row['month']]++;
    $year_counts[$row['year']]++;
}

# most recent year first!
krsort($by_year);

# and now iterate for display
foreach ($by_year as $year => $months){

    echo "<b>$year</b> ($year_counts[$year])<br />\n";
    echo "<ul>\n";

    # sort jan->dec
    ksort($months);
    foreach ($months as $month => $num){

        $name = date('F', mktime(0,0,0,$month,1,2010));
        echo "<li> $name ($num) </li>\n";
    }

    echo "</ul>\n";
}

这可以按照您的要求使用此输入数据：

$rows = array(
    array('year' => 2012, 'month' => 3),
    array('year' => 2012, 'month' => 3),
    array('year' => 2012, 'month' => 2),
    array('year' => 2011, 'month' => 1),
);

输出：

2012 (3)
 * February (1)
 * March (2)
2011 (1)
 * January (1)

*已更新以显示年份数

Answer 2

然后你可以像这样构建数组：

$someArray = Array();
$query = mysql_query(...);

while (($row = mysql_fetch_assoc($query)) != NULL)
{
    $someArray[] = Array("year" => $row['year'], "month" => $row['month']);
}

在这种情况下，$someArray[]是“将此元素附加到数组上”的表示法。

Answer 3

我猜你正在尝试创建一个每月有多少篇文章的列表，按年份按层次显示？

Neil的答案显示了如何从数据库中获取结果。如果您将其作为起点，那么您可以遍历数组并使用计数构建列表，然后打印出列表。

您也可以让MySQL使用group by语句计算每月的帖子数。

select year(post_date) as `year`, month(post_date) as `month`, count(*) as `count`
from posts
group by concat(year(post_date),month(post_date))
order by post_date desc

然后使用类似于Neil的代码，但为了以后的方便而制作一些嵌套数组，你得到：

$counts = array();
$query = mysql_query(...);

while (($row = mysql_fetch_assoc($query)) != null) {
    $counts[ $row['year'] ] = array("month" => $row['month'], 'count' => $row['count']);
}

然后将其打印为HTML：

echo "<ul>";
foreach($counts as $year => $months) {
    echo "<li>$year <ul>"
    foreach($months as $row) {
        $month = name_for_month($row['month']); //TODO: make this method
        echo "<li>$month ({$row['count']})</li>";
    }
    echo "</ul></li>";
}
echo "</ul>";

嗯，你也有一年的总数。好吧，你可以添加类似的东西：

$yearSums = array();
$counts = array();
$query = mysql_query(...);

while (($row = mysql_fetch_assoc($query)) != null) {
    $counts[ $row['year'] ] = array("month" => $row['month'], 'count' => $row['count']);
    $yearSums[ $row['year'] ] += $row['count'];
}

然后打印出那些数据。

免责声明：不保证这是好的代码，这只是一个如何做到这一点的简单示例。

如何从php中的日期数组创建存档列表

3 个答案: