Question

我有2个日期数组。我需要最有效的方法来构建第三个日期数组，其中只包含2个日期数组中相同的日期。

例如：

List of Dates #1:
2017-01-01
2017-01-02
2017-01-03
2017-02-01
2017-02-02
2017-09-09

List of Dates #2:
2017-01-01
2017-02-01
2017-03-01
2017-04-01

So array 3 should be:
2017-01-01
2017-02-01

Answer 1

您正在寻找array_intersect：

工作演示：https://eval.in/862254

$array1 = array("2017-01-01", "2017-01-01" ,"2017-01-02","2017-01-03","2017-02-01", "2017-02-02","2017-09-09");

$array2 = array("2017-01-01","2017-02-01","2017-03-01","2017-04-01");
$result = array_intersect(array_unique($array1), $array2);
echo "<pre>";
print_r($result);

输出：

Array
(
    [0] => 2017-01-01
    [3] => 2017-02-01
)

注意

array_intersect返回包含所有值的数组 $array1，其值存在于所有参数中。所以，如果你的 $array1具有重复数据，然后结果数组也有重复值。

我已添加array_unique来克服这种情况。

Answer 2

也许 array_intersect（）？

$array1 = array ("a" => "green", "red", "blue");
$array2 = array ("b" => "green", "yellow", "red");
$result = array_intersect ($array1, $array2);

结果

Array
(
    [a] => green
    [0] => red
)

Answer 3

试试这个

function myfunction($a,$b)
{
if ($a===$b)
  {
  return 0;
  }
  return ($a>$b)?1:-1;
}

$a1=array("a"=>"red","b"=>"green","c"=>"blue","yellow");
$a2=array("A"=>"red","b"=>"GREEN","yellow","black");
$a3=array("a"=>"green","b"=>"red","yellow","black");

$result=array_uintersect($a1,$a2,$a3,"myfunction");
print_r($result);

结果：

Array ( [a] => red [0] => yellow )

如何从PHP中的现有日期数组创建新的日期数组？

3 个答案: