如何将str
的{{1}}表示形式(例如以下字符串)转换为dict
?
dict
我不想使用s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
。我还能用什么呢?
这个的主要原因是我写的一个同事课程,将所有输入转换为字符串。我没心情去修改他的课程,以解决这个问题。
答案 0 :(得分:996)
从Python 2.6开始,您可以使用内置的ast.literal_eval
:
>>> import ast
>>> ast.literal_eval("{'muffin' : 'lolz', 'foo' : 'kitty'}")
{'muffin': 'lolz', 'foo': 'kitty'}
这比使用eval
更安全。正如自己的文档所说:
>>> help(ast.literal_eval) Help on function literal_eval in module ast: literal_eval(node_or_string) Safely evaluate an expression node or a string containing a Python expression. The string or node provided may only consist of the following Python literal structures: strings, numbers, tuples, lists, dicts, booleans, and None.
例如:
>>> eval("shutil.rmtree('mongo')")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<string>", line 1, in <module>
File "/opt/Python-2.6.1/lib/python2.6/shutil.py", line 208, in rmtree
onerror(os.listdir, path, sys.exc_info())
File "/opt/Python-2.6.1/lib/python2.6/shutil.py", line 206, in rmtree
names = os.listdir(path)
OSError: [Errno 2] No such file or directory: 'mongo'
>>> ast.literal_eval("shutil.rmtree('mongo')")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/opt/Python-2.6.1/lib/python2.6/ast.py", line 68, in literal_eval
return _convert(node_or_string)
File "/opt/Python-2.6.1/lib/python2.6/ast.py", line 67, in _convert
raise ValueError('malformed string')
ValueError: malformed string
答案 1 :(得分:168)
http://docs.python.org/2/library/json.html
JSON可以解决这个问题,虽然它的解码器需要围绕键和值的双引号。如果你不介意替换黑客......
import json
s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
json_acceptable_string = s.replace("'", "\"")
d = json.loads(json_acceptable_string)
# d = {u'muffin': u'lolz', u'foo': u'kitty'}
请注意,如果您将单引号作为键或值的一部分,则由于不正确的字符替换而失败。只有在您对eval解决方案有强烈反感时,才建议使用此解决方案。
有关json单引号的更多信息:jQuery single quote in JSON response
答案 2 :(得分:120)
使用json.loads
:
>>> import json
>>> h = '{"foo":"bar", "foo2":"bar2"}'
>>> type(h)
<type 'str'>
>>> d = json.loads(h)
>>> d
{u'foo': u'bar', u'foo2': u'bar2'}
>>> type(d)
<type 'dict'>
答案 3 :(得分:27)
以OP为例:
s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
我们可以使用Yaml来处理字符串中的这种非标准json:
>>> import yaml
>>> s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
>>> s
"{'muffin' : 'lolz', 'foo' : 'kitty'}"
>>> yaml.load(s)
{'muffin': 'lolz', 'foo': 'kitty'}
答案 4 :(得分:21)
如果字符串始终可信,则可以使用eval
(或按照建议使用literal_eval
;无论字符串是什么,它都是安全的。)否则您需要解析器。如果JSON解析器(例如simplejson)只存储符合JSON方案的内容,它将起作用。
答案 5 :(得分:19)
使用json
。 ast
库消耗大量内存并且速度较慢。我有一个需要读取156Mb文本文件的进程。 Ast
转换字典json
延迟5分钟,内存减少60%!
答案 6 :(得分:6)
你可以试试这个。
>>> import ast
>>> data = "{'user': 'bob', 'age': 10, 'grades': ['A', 'F', 'C']}"
>>> ast.literal_eval(data)
O/P: {'age': 10, 'grades': ['A', 'F', 'C'], 'user': 'bob'}
>>> user = ast.literal_eval(data)
>>> user['age']
O/P: 10
>>> user['grades']
O/P: ['A', 'F', 'C']
>>> user['user']
O/P: 'bob'
答案 7 :(得分:5)
如果你不能使用Python 2.6,你可以使用简单的safeeval implmentntation,如http://code.activestate.com/recipes/364469/
它背负着Python编译器,所以你不必自己完成所有的工作。
答案 8 :(得分:5)
string = "{'server1':'value','server2':'value'}"
#Now removing { and }
s = string.replace("{" ,"")
finalstring = s.replace("}" , "")
#Splitting the string based on , we get key value pairs
list = finalstring.split(",")
dictionary ={}
for i in list:
#Get Key Value pairs separately to store in dictionary
keyvalue = i.split(":")
#Replacing the single quotes in the leading.
m= keyvalue[0].strip('\'')
m = m.replace("\"", "")
dictionary[m] = keyvalue[1].strip('"\'')
print dictionary
答案 9 :(得分:4)
总结:
import ast, yaml, json, timeit
descs=['short string','long string']
strings=['{"809001":2,"848545":2,"565828":1}','{"2979":1,"30581":1,"7296":1,"127256":1,"18803":2,"41619":1,"41312":1,"16837":1,"7253":1,"70075":1,"3453":1,"4126":1,"23599":1,"11465":3,"19172":1,"4019":1,"4775":1,"64225":1,"3235":2,"15593":1,"7528":1,"176840":1,"40022":1,"152854":1,"9878":1,"16156":1,"6512":1,"4138":1,"11090":1,"12259":1,"4934":1,"65581":1,"9747":2,"18290":1,"107981":1,"459762":1,"23177":1,"23246":1,"3591":1,"3671":1,"5767":1,"3930":1,"89507":2,"19293":1,"92797":1,"32444":2,"70089":1,"46549":1,"30988":1,"4613":1,"14042":1,"26298":1,"222972":1,"2982":1,"3932":1,"11134":1,"3084":1,"6516":1,"486617":1,"14475":2,"2127":1,"51359":1,"2662":1,"4121":1,"53848":2,"552967":1,"204081":1,"5675":2,"32433":1,"92448":1}']
funcs=[json.loads,eval,ast.literal_eval,yaml.load]
for desc,string in zip(descs,strings):
print('***',desc,'***')
print('')
for func in funcs:
print(func.__module__+' '+func.__name__+':')
%timeit func(string)
print('')
结果:
*** short string ***
json loads:
4.47 µs ± 33.4 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)
builtins eval:
24.1 µs ± 163 ns per loop (mean ± std. dev. of 7 runs, 10000 loops each)
ast literal_eval:
30.4 µs ± 299 ns per loop (mean ± std. dev. of 7 runs, 10000 loops each)
yaml load:
504 µs ± 1.29 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
*** long string ***
json loads:
29.6 µs ± 230 ns per loop (mean ± std. dev. of 7 runs, 10000 loops each)
builtins eval:
219 µs ± 3.92 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
ast literal_eval:
331 µs ± 1.89 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
yaml load:
9.02 ms ± 92.2 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
结论: 喜欢 json.loads
答案 10 :(得分:3)
没有使用任何lib:
dict_format_string = "{'1':'one', '2' : 'two'}"
d = {}
elems = filter(str.isalnum,dict_format_string.split("'"))
values = elems[1::2]
keys = elems[0::2]
d.update(zip(keys,values))
注意:由于硬编码split("'")
仅适用于数据为&#34;单引号&#34;的字符串。
答案 11 :(得分:1)
Siva Kameswara Rao Munipalle 代码优化
s = s.replace("{", "").replace("}", "").split(",")
dictionary = {}
for i in s:
dictionary[i.split(":")[0].strip('\'').replace("\"", "")] = i.split(":")[1].strip('"\'')
print(dictionary)