我试图以秒为单位计算两个日期之间的日间时间和夜间时间,假设“夜间时间”定义为上午8:00到上午7:59,“白天时间”定义为8: 00:00到7:59 PM。我将与当前时间戳进行比较的过去日期总是不到24小时。
我该怎么做?
答案 0 :(得分:4)
当您开始处理夏令时等时,这很快变得复杂,因此您确实需要使用当前日历并使用日历/日期函数来计算时差。
例如,如果时钟在凌晨3:00向前移动1小时,那么您应该在时间变化当天按照您的定义进行11小时的“夜晚”(而不是12小时)。
我还没有彻底测试过这段代码,但它应该非常接近:
// 8:00:00 AM in seconds
static const NSTimeInterval daytimeStart = 28800;
// 8:00:00 PM in seconds
static const NSTimeInterval daytimeStop = 72000;
// Convert date to a "time" which is the number of seconds since midnight, NOT considering time changes
- (NSTimeInterval)getTimeForDate:(NSDate *)date {
NSCalendar *cal = [NSCalendar currentCalendar];
NSDateComponents *dateComps = [cal components:NSHourCalendarUnit |
NSMinuteCalendarUnit |
NSSecondCalendarUnit
fromDate:date];
NSTimeInterval time = dateComps.hour * 3600 + dateComps.minute * 60 + dateComps.second;
return time;
}
// Set the time to the specified hour and minutes/seconds to 0
- (NSDate *)dateBySettingTimeToBeginningOfHour:(NSUInteger)hour ofDate:(NSDate *)date {
NSCalendar *cal = [NSCalendar currentCalendar];
NSDateComponents *dateComps = [cal components:NSYearCalendarUnit |
NSMonthCalendarUnit |
NSDayCalendarUnit |
NSHourCalendarUnit |
NSMinuteCalendarUnit |
NSSecondCalendarUnit
fromDate:date];
[dateComps setHour:hour];
[dateComps setMinute:0];
[dateComps setSecond:0];
NSDate *newDate = [cal dateFromComponents:dateComps];
return newDate;
}
// Add one day to the current date
- (NSDate *)dateByAddingOneDayToDate:(NSDate *)date {
NSCalendar *cal = [NSCalendar currentCalendar];
NSDateComponents *dateComps = [cal components:NSYearCalendarUnit |
NSMonthCalendarUnit |
NSDayCalendarUnit |
NSHourCalendarUnit |
NSMinuteCalendarUnit |
NSSecondCalendarUnit
fromDate:date];
[dateComps setDay:[dateComps day] + 1];
NSDate *newDate = [cal dateFromComponents:dateComps];
return newDate;
}
// Check to see if it is daytime
- (BOOL)isDayForDate:(NSDate *)date {
NSTimeInterval time = [self getTimeForDate:date];
if (time >= daytimeStart) {
if (time < daytimeStop) {
return YES;
}
}
// Default
return NO;
}
// Check to see if it is night
- (BOOL)isNightForDate:(NSDate *)date {
return ![self isDayForDate:date];
}
// When do we transition from day to night or night to day next?
- (NSDate *)dateForNextTransitionForDate:(NSDate *)date {
NSTimeInterval time = [self getTimeForDate:date];
if (time < daytimeStart) {
return [self dateBySettingTimeToBeginningOfHour:8 ofDate:date];
}
if (time < daytimeStop) {
return [self dateBySettingTimeToBeginningOfHour:20 ofDate:date];
}
// Tomorrow morning
NSDate *newDate = [self dateByAddingOneDayToDate:date];
newDate = [self dateBySettingTimeToBeginningOfHour:8 ofDate:newDate];
return newDate;
}
- (NSTimeInterval)nightTimeFromDate:(NSDate *)startingDate toDate:(NSDate *)laterDate {
if ([startingDate compare:laterDate] != NSOrderedAscending) {
return 0;
}
NSTimeInterval nightTime = 0;
NSDate *now = laterDate;
NSDate *transitionDate = startingDate;
NSDate *loopDate = startingDate;
BOOL isNight = [self isNightForDate:startingDate];
do {
transitionDate = [self dateForNextTransitionForDate:transitionDate];
if ([transitionDate compare:now] == NSOrderedDescending) {
transitionDate = now;
}
if (isNight) {
nightTime = nightTime + [transitionDate timeIntervalSinceDate:loopDate];
}
loopDate = transitionDate;
isNight = !isNight;
} while ([transitionDate compare:now] != NSOrderedSame);
return nightTime;
}
- (NSTimeInterval)dayTimeFromDate:(NSDate *)startingDate toDate:(NSDate *)laterDate {
if ([startingDate compare:laterDate] != NSOrderedAscending) {
return 0;
}
NSTimeInterval diff = [laterDate timeIntervalSinceDate:startingDate];
diff = diff - [self nightTimeFromDate:startingDate toDate:laterDate];
return diff;
}
// Example usage:
NSDate *now = [NSDate date];
NSDate *date = [NSDate dateWithTimeInterval:-82800 sinceDate:now];
NSLog(@"%f", [self nightTimeFromDate:date toDate:now]);
NSLog(@"%f", [self dayTimeFromDate:date toDate:now]);
// Results are 43200.000000 and 39600.000000 right now in the middle of the day.
答案 1 :(得分:1)
白天时间=((今天和最后一天之间的天数)* 12)+(今天的白天小时数)+(最后一天的白天小时数)
夜间时间=((今天和最后一天之间的天数)* 12)+(今天的夜间时间#)+(最后一天的夜间时数#)
修改强>
int dthours = 0, nthours = 0;
dthours += ternary with a calculation of 24 - starthour logic for daytime
nthours += ternary with a calculation of 24 - starthour logic for nighttime
dthours += ternary with a calculation of endhour logic for daytime
nthours += ternary with a calculation of endhour logic for nighttime
明天夜间的逻辑看起来像是:
nthours += (endhour - 4 > 0) ? ((endhour - 16 > 0) ? endhour - 12 : 4) : endhour;